DC-10
At t=0 the altidude is 4500 feet
It's descending at a rate of 150 feet per minute, then each 5 minutes it descends (150 feet/min)(5 min)=750 feet. Then:
At t=5 the altitude is 4500 feet-750 feet=3750 feet
At t=10 the altitude is 3750 feet-750 feet=3000 feet
727
At t=0 the altidude is 600 feet
It's climbing at a rate of 75 feet per minute, then each 5 minutes it climbs (75 feet/min)(5 min)=375 feet. Then:
At t=5 the altitude is 600 feet+375 feet=975 feet
At t=10 the altitude is 975 feet+375 feet=1350 feet
The graph with these characteristics is Graph B.
Answer: The graph B shows when the two planes will be at the same altitude
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
Answer: Area of a right circular Cylinder--- curved surface area -2πrh Total surface area -2πr(r+h),where 'r' is the radius of the circular surface and 'h' is the height of the cylinder.
Answer:
V≈461.81cm³
Step-by-step explanation:
11.5 is a rational number