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2 years ago

Please answer quickly with little explanation

Mathematics

1 answer:

eimsori [14]2 years ago

6 0

What’s the question

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Help with this question it's PEMDAS

Dafna11 [192]

[3*(2+4)] -4

Parenthesis first:

[3 * 6] -4

Brackets next:

18 - 4

Now subtract:

18-4 = 14

The answer is C. 14

7 0

2 years ago

Read 2 more answers

Aaron has 16 blue pens and 12 red pens.

Maslowich

Answer:

Step-by-step explanation:

16÷4=4 12÷3=4 meaning is.the lowest common multiple

7 0

2 years ago

One of my factors is equal to 5-2. I am the product 24. What are my other factors?

blsea [12.9K]

5 - 2 = 3

3 x ? = 24
(24 ÷ 3 = 8)
3 x 8 = 24

7 0

2 years ago

Read 2 more answers

Factories and other industrial users account for about 23/50 of the total water usage in the United States. Which of the followi

mihalych1998 [28]

23 / 50 = 0.46

0.46 converted to a percent is 46%

6 0

2 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

2 years ago