3 years ago

Let f(×) = x - 2 and g(x) = x2- 7x -9

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

what are we trying to Solve for?

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Log 10(x + 3) – log 10(x-3) = 1

nadezda [96]

Answer:33/9

Step-by-step explanation:

Log10(x+3)-Log10(x-3)=1

Log10((x+3)/(x-3))=1

(x+3)/(x-3)=10^1

(x+3)/(x-3)=10

Cross multiply

x+3=10(x-3)

Open brackets

x+3=10x-30

Collect like terms

10x-x=30+3

9x=33

Divide both sides by 9

9x/9=33/9

x=33/9

4 0

4 years ago

the mass of a sphere made of gold is proportional to the diameter, d, cubed. express the mass m of the sphere as a function of t

elixir [45]

Answer:

m = cd³

Step-by-step explanation:

mass of is proportional to the diam

sphere cubed

Symbolically, this can be written as:

m = cd³

4 0

3 years ago

Need help will give brainiest!!!!!

Snowcat [4.5K]

Answer:

Step-by-step explanation:

6 0

3 years ago

a meteorologist who sampled 13 randomly selected thunderstorms found that the average speed at which they traveled across a cert

GalinKa [24]

Answer:

Step-by-step explanation:

13x17

4 0

2 years ago

the temperature fell from o degrees to 6 3/5 degrees below 0 in 2 1/5 hours. what was the temperature change per hour?

Kay [80]

<u>Answer:</u>

The temperature change per hour was -3 degrees per hour.

<u>Step-by-step explanation:</u>

We know that the temperature fell from $0$ degrees to $-6\frac{3}{5}$ degrees in a time period of $2\frac{1}{5}$ hours.

So to find the rate of change of the temperature, we will divide the change in temperature by the number of hours.

For that, we will change the mixed number into improper fractions and then solve:

$-6\frac{3}{5}=-\frac{33}{5}degrees$

$2\frac{1}{5}=\frac{11}{5} hours$

Temperature change per hour = $\frac{-\frac{33}{5}}{\frac{11}{5}} = \frac{33}{5}*-\frac{5}{11}=-3$

Therefore, the temperature change per hour was -3 degrees per hour.

7 0

3 years ago