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Maksim231197 [3]

2 years ago

7

lisa buys 12 packs of juice boxes that are on sale and pays a total of $48. Use a ratio table to determine how much lisa will pa

y to buy 8 more packs of juice boxes at the same store

1 answer:

Verizon [17]2 years ago

5 0

Answer:

Step-by-step explanation:

1 pack of boxes= 48/12= 4

Thus, 8 packs of boxes = 4*8=32.

Hopefully this satisfies you

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A trade magazine routinely checks the drive-through service times of fast-food restaurants. Upper AA 9595% confidence interva

Butoxors [25]

Answer:

One can be 95% confident that the drive-through service times of fast-food chain is between 169 seconds and 172 seconds.

Step-by-step explanation:

The confidence interval gives a range of value for the population mean or parameter, which is calculated from the statistic value of the data (that is sample statistic). This range gives the interval which is associated with a certain level of confidence for which the interval will contain the true value of the unknown parameter (true value). In the scenario above, the associated confidence level is 95%.Hence, we can be 95% confident that the true value will be continued with the interval (169 ; 172)

6 0

3 years ago

Needd helpp pleasee!!!!!

Morgarella [4.7K]

Number of game tokens is the label on x-axis.

<u>Step-by-step explanation</u>:

The equation is y = 0.5x + 3

Given,

Admission charge = $3
Cost of game token = $0.5 per game.

Total cost = admission charge + cost for number of game token

where,

y represents the total cost
x represents the number of game tokens.

7 0

2 years ago

What did sin theta/theta whisper worksheet answer key worksheet?

djyliett [7]

To evaluate
$\lim_{\theta \to 0} \frac{\sin\theta}{\theta}$

First, we input 0, for theta in the function to obtain:
$\frac{\sin0}{0} = \frac{0}{0}$

This is an indeterminate form.

So, we apply L'Hopital's rule by differentiating the numerator and the denominator as follows:

$\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=\lim_{\theta \to 0} \frac{ \frac{d}{d\theta} (\sin\theta)}{\frac{d}{d\theta}\theta} \\ \\ =\lim_{\theta \to 0} \frac{\cos\theta}{1}=\cos0=1$

7 0

2 years ago

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form

Alex787 [66]

Answer:

$y=-\frac{2}{5}x-\frac{1}{5}$

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

m is the slope

b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

$m = -\frac{2}{5}$

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

$y=-\frac{2}{5}x + b$

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-3,1). When x of the line is -3, y of the line must be 1.
(2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: $y=-\frac{2}{5}x + b$ . $b$ is what we want, the - $-\frac{2}{5}$ is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

(-3,1). y = mx + b or $1=-\frac{2}{5} * -3 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(-3)$ . $b = -\frac{1}{5}$ .
(2,-1). y = mx + b or $-1=-\frac{2}{5} * 2 + b$ , or solving for b: $b = 1-(-\frac{2}{5})(2)$ . $b = -\frac{1}{5}$ .

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points (-3,1) and (2,-1) is $y=-\frac{2}{5}x-\frac{1}{5}$

8 0

2 years ago

Solve the equation15=2y-5

Lesechka [4]

15 = 2Y - 5
20 = 2Y
10 = Y

5 0

3 years ago