Answer:
The solution is the point (-2,-2)
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by substitution
substitute equation A in equation B

Solve for x

Find the value of y
substitute the value of x in the equation A

so

therefore
The solution is the point (-2,-2)
0.16666666666..... (6 recurring)
1a);greatest to least, (3.5)^2, 57/5, 6 square root of 3, 9.8, and square root of 75
1.b) you put each in a calculator to find the values in decimal form
Answer:
(1 ) Inner curved surface area of the well is 109.9 sq. meters.
(2) The cost of plastering the total curved surface area is 4396.
Step-by-step explanation:
The inner diameter = 3.5 m
Depth of the well = 10 m
Now, Diameter = 2 x Radius
⇒R = D/ 2 = 3.5/2 = 1.75
or, the inner radius of the well = 1.75 m
CURVED SURFACE AREA of cylinder = 2πr h
⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)
= 109 sq. meters
Hence, the inner curved surface area of the well is 109.9 sq. meters.
Now, the cost of plastering the curved area is 40 per sq meters
So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)
= 109.9 x (40)
= 4396
Hence, the cost of plastering the total curved surface area is 4396.