Ask question

Ask question

All categories

2 years ago

7

Cliff is trying to make a set of parallel lines in a coordinate plane intersect at a perpendicular angle. Which strategy would w

ork?
A) Only rotate one line
B) Translate them to the right
C) Rotate them 180°
D) Reflect them across the X-axis

1 answer:

joja [24]2 years ago

7 0

C I think but not sure sorry if it’s got wronge

You might be interested in

Which expression is equivalent to sin^2x-sin x-2/sin x-2

Arturiano [62]

Post the problem from the paper

3 0

2 years ago

Write words to match the expressions

velikii [3]

Cat-Pat
Mat-Rat
Soup-Group

3 0

2 years ago

This is pretty easy :0

maksim [4K]

Answer:

1, 1.5, -1 1/5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Plz help i need to turn dis in now

Gnesinka [82]

Answer:

b because if your going to the left that means is negative and we are going up that means it's positive

8 0

3 years ago

Read 2 more answers

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago