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Ugo [173]
3 years ago
10

I need help please! Thank you!

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

1, because 13 does not divide by anything by 1 that 20 dived to also

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8 0
3 years ago
Write the standard equation for the circle center (-6,8) that passes through (0,0)
Reil [10]

Answer:

D

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 6, - 8), thus

(x + 6)² + (y + 8)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 6, - 8) and (x₂, y₂ ) = (0, 0)

r = \sqrt{(0+6)^2+(0+8)^2} = \sqrt{36+64} = \sqrt{100} = 10

Hence

(x + 6)² + (y + 8)² = 100 → D

4 0
3 years ago
Y=-1/9x-4 Which of the following is the equation of a line that is parallel?
fenix001 [56]

Any line with a slope of -1/9 will be parallel

4 0
3 years ago
4a/3-b/4=6<br> 5a/6+b=13<br> Solve linear system by elimination
kondor19780726 [428]
\bf \cfrac{4a}{3}-\cfrac{b}{4}=6&#10;\qquad \qquad &#10;\cfrac{5a}{6}+b=13&#10;\\\\\\&#10;\textit{let us remove the denominators off those folks}\\&#10;\textit{by multiplying the first one by 12, both sides}\\&#10;\textit{and the second one by 6, both sides, thus}&#10;\\\\\\&#10;12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72&#10;\\\\\\&#10;6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78

\bf  \textit{now, let's do the elimination}&#10;\\\\&#10;&#10;\begin{array}{llll}&#10;16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\&#10;5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\&#10;&&--------\\&#10;&&58a+0\quad=372&#10;\end{array}

solve for "a", once you get "a", plug it back into either equation to get "b"
3 0
3 years ago
How to answer this question??? <br>thanks
vesna_86 [32]
\dfrac{2m}{5}+3=7(4m-3)\ \ \ \ |use\ distributive\ property:a(b-c)=ab-ac\\\\\dfrac{2m}{5}+3=28m-21\ \ \ \ \ |multiply\ both\ sides\ by\ 5\\\\2m+15=140m-105\ \ \ \ |subtract\ 140m\ from\ both\ sides\\\\-138m+15=-105\ \ \ \ |subtract\ 15\ from\ both\ sides\\\\-138m=-120\ \ \ \ |divide\ both\ sides\ by\ (-138)\\\\m=\dfrac{120:6}{138:6}\\\\\boxed{m=\frac{20}{23}}
7 0
3 years ago
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