+3 to both sides and you get s = -7
A. The coordinates of the midpoint of CD in terms of p and q is [(4 + p) / 2 , (5 + q) / 2]
B. The coordinates of D, Given that the midpoint of CD is (7, 1) is (10 , -3)
<h3>A. How to determine the mid point</h3>
- Coordinate of C = (4, 5)
- Coordinate of D = (p, q)
- Mid point =?
Mid point = (X , Y)
X = (x₁ + x₂) / 2
X = (4 + p) / 2
Y = (y₁ + y₂) / 2
Y = (5 + q) / 2
Thus,
Mid point = (X , Y)
Mid point = [(4 + p) / 2 , (5 + q) / 2]
<h3>B. How to determine the coordinates of D</h3>
- Mid point = (7, 1)
- Coordinates of D =?
Mid point = (7, 1) = (X , Y)
X = (4 + p) / 2
7 = (4 + p) / 2
Cross multiply
7 × 2 = 4 + p
14 = 4 + p
Collect like terms
p = 14 - 4
p = 10
Y = (5 + q) / 2
1 = (5 + q) / 2
Cross multiply
1 × 2 = 5 + q
2 = 5 + q
Collect like terms
q = 2 - 5
q = -3
Coordinates of D = (p, q)
Coordinates of D = (10 , -3)
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Answer:
51.3 degrees
Step-by-step explanation:
Use Trig Ratio to solve for theta aka the angle formed between the ;adder and the ground.
So we have the hypotenuse = 24ft and the adjacent = 15ft so I am going to use the cos ratio.
cos ∅ = a/h
rearrange for theta
∅ = cos -1 ( a/h)
now sub in the information
∅ = 51.3178
now round to the nearest tenth
∅ = 51.3 degrees
write your therefore statement
therefore, the angle between the ladder and the ground is 51.3 degrees.
Answer:
Step-by-step explanation:
