What is the value of x?
1 answer:
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Answer:
The result is the same.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
Given the information:
- square 12 inches wide
- 3-inch diameter cookies are cut => its radius is: 1.5 inches
Hence we can find some information:
- The area of the square is:
square inches
- The area of a cookies is:
π = 3.14*
= 7.065 square inches
- The total number of 3-inch cookies are: 4*4 =16
=> The total area of the cookies is: 16* 7.065 = 113.04 square inches
=> how much cookie dough is "wasted" when 3-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
If the diameter is increased to 4 inches => its radius: 2 inches, we have:
- The area of a cookies is:
square inches
- The total number of 3-inch cookies are: 3*3 =9
=> The total area of the cookies is: 9* 12.56 = 113.04 square inches
=> how much cookie dough is "wasted" when 4-inch cookies are cut:
= The area of the square - The total area of the cookies
= 144 - 113.04 = 30.96 square inches
The result is the same.
Answer:
Null and alternative hypothesis
Test statistic
P-value
The null hypothesis is rejected.
It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.
Step-by-step explanation:
We have to perform a hypothesis test of a proportion.
The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:
The signifiance level is 0.01.
The sample has a proportion p=0.1 and sample size of n=6000.
The standard deviation of the proportion, needed to calculate the test statistic, is:
The test statistic is calculated as:
As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.
Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.