This strategy works because if you subtract one number from another the sum of the two numbers should be the that is being subtracted from. (In this case, it's 200)
let the width of the rectangle be x
area of rectangle is l*b
x * (x + 6) = 40^2
x^2 + 6x = 40^2
x^2 + 6x = 1600
x + 6x =√1600
x + 6x = 40
7x = 40
x = 5.7
Hope you found this useful
The question is incomplete as the cost price isn't given. However, taking the cost price as x :
Answer:
Kindly check explanation
Step-by-step explanation:
Given :
A car costs$cents when new. It was sold for four fifths of its cost price. How much money was lost on the car.
Let :
Cost price when new = x
Cost price when sold = 4/5 * cost price when new
Cost when sold = 4/5 of x = 4x/5
Amount of money lost on the car = (Cost price of car when new - Cost of car when sold)
Hence,
Amount of money lost on the car = (x - 4x/5)
x - 4x/5 = (5x - 4x) / 5 = x / 5
To obtain the exact price, kindly input the omitted cost when new for x.
Answer:
f(3)=21
Step-by-step explanation:
f(1)=3
f(n)=2f(n-1)+3
n=2
f(2)=2f(2-1)+3
f(2)=2f(1)+3
f(2)=2*3+3
f(2)=6+3
f(2)=9
n=3
f(3)=2f(3-1)+3
f(3)=2f(2)+3
f(3)=2*9+3
f(3)=18+3
f(3)=21
