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Lyrx [107]
4 years ago
7

How do I answer this question?

Mathematics
1 answer:
Yuliya22 [10]4 years ago
5 0
They are similar in everything other than the inquality which make <> or eqaul to. ineqaulity tells us if the value is great or less then than what we want, etc.
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In right triangle XYZ, triangle Y is the right angle and m angleX = 60 degrees. If YZ= 4 what is XY
Marina86 [1]

Answer:

XY = \frac{4\sqrt 3}{3}

Step-by-step explanation:

<em>The question is illustrated with the attached figure.</em>

Required

Determine XY

To solve for XY, we make use of the tan function, which states that:

tan\theta = \frac{Opposite}{Hypotenuse}

In this case:

tan\ 60= \frac{YZ}{XY}

Substitute 4 for YZ

tan\ 60= \frac{4}{XY}

Make XY the subject

XY= \frac{4}{tan\ 60}

tan\ 60 =\sqrt 3

So, the expression becomes:

XY = \frac{4}{\sqrt 3}

Rationalize:

XY = \frac{4 * \sqrt 3}{\sqrt 3 * \sqrt 3}

XY = \frac{4\sqrt 3}{3}

3 0
3 years ago
Read 2 more answers
A triangle has side lengths 11, 12, and 15. Is it acute, obtuse, or right?
Sedbober [7]

Answer:

right triangle

Step-by-step explanation:

because 15 would be the base so 11 and 12 would be the sides and fot the triangle to be acute or obtuse the total of the sides (11+12) has to be lass than the base (15), but it is more 23 so it has to be a right triangle.

8 0
3 years ago
Can someone pls help me
Ivan

Answer:

arc EFC = 237°

Step-by-step explanation:

arc DEF = 140°

arc EF = 140° - 83° = 57°

arc DC = arc FG

arc DC = (360° - 140° - 140°)/2 = 40°

arc EFC = arc CG + arc FG = arc EF = 140° + 40° + 57° = 237°

8 0
3 years ago
In standard notation, 7.09 �� 10 *to the power of 4* is _____.
forsale [732]

Answer:

70,900

Step-by-step explanation:


3 0
3 years ago
Complete the table of values for the function f(x) = (1/3)x for a, b, and c. x : -2, -1, 0, 1, 2. f(x) : a, b, c, 1/3, 1/9
balu736 [363]

Given:

The function is

f(x)=\left(\dfrac{1}{3}\right)^x

To find:

The missing values for a, b, and c in the given table.

Solution:

We have,

f(x)=\left(\dfrac{1}{3}\right)^x

At x=-2,

f(-2)=\left(\dfrac{1}{3}\right)^{-2}

a=\left(3\right)^{2}         \left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]

a=9

At x=-1,

f(-1)=\left(\dfrac{1}{3}\right)^{-1}

b=\left(3\right)^{1}         \left[\because \left(\dfrac{a}{b}\right)^{-n}=\left(\dfrac{b}{a}\right)^{n}\right]

b=3

At x=0,

f(0)=\left(\dfrac{1}{3}\right)^{0}

c=1         \left[\because a^0=1, a\neq 0\right]

Therefore, the missing values of a,b and c are 9, 3, and 1 respectively.

8 0
3 years ago
Read 2 more answers
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