Answer:
2x^2 + x - 1
If I did anything you didn't understand let me know so I can explain.
Step-by-step explanation:
All of them are quadratics so let's use that.
The first one is 2x^2 + x - 1. To find the axis of symmetry the strategy is usually to find the two zeroes of a quadratic and pick the number between them. Something to notice though is that 2x^2 + x - 1 is just 2x^2 + x sshifted down 1, so they both have the same axis of symmetry. So I am going to ignore the constant, because then finding the zeroes is much much simpler. I am going to do this with all opions.
So 2x^2 + x - 1 I am just going to use 2x^2 + x. If you factor out an x you get x(2x + 1) So now we have it in factored form and we know the zeroes are 0 and -1/2. The number directly in between these is -1/4, so the axis of symmetry is x = -1/4. I don't know if there is only one with that axis of symmetry so i am going to check the rest.
2x^2 - x + 1 means we are only going to look at 2x^2 - x. factoring we get x(2x - 1) so the zeroes are 0 and 1/2, so the axis of symmetry is at 1/4.
x^2 + 2x - 1 we only use x^2 + 2x. Factored form is x(x+2) so zeroes are 0 and -2 whichh means axis of symmetry is -1
x^2 - 2x + 1 has the same axis of symmetry as x^2 - 2x, which has zeros at 0 and 2 so the axis of symmetry is at 1.
So yep, it was just the first one.
Here's your answer to the first problem
The answer is y = 3/4 x + 2
<em>Explanation:</em>
Basically, the formula for a linear equation is y = mx + b
b = y-intercept
mx = slope
slope = rise/ run (pos.)
it can also be fall/ crawl (neg.)
In the graph the line meets at the y-int. at 2, the line rises 3 and goes right 4 each time.
Answer:
y = -1/3x -3
Step-by-step explanation:
-2x - 6y = 18
We want to solve for y since the slope intercept form is y =mx+b where m is the slope and b is the y intercept
Add 2x to each side
-2x-6y +2x = 2x+18
-6y = 2x+18
Divide each side by -6
-6y/-6 = 2x/-6 + 18/-6
y = -1/3x -3
This is in slope intercept form with the slope -1/3 and the y intercept -3
