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3 years ago

Select the correct answer from each drop down menu. Complete the statements about the closure of sets.

Mathematics

1 answer:

anygoal [31]3 years ago

4 0

Answer:

not closed

included

closed

included

Step-by-step explanation:

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Help please For the following function, construct a table.

AysviL [449]

Answer:

See the attachment below.

Step-by-step explanation:

Best Regards!

3 0

3 years ago

Find f(x) = 4*, when x = 1/2

faust18 [17]

Answer:

f=8

Step-by-step explanation:

fx0.5=4

f=4x2

f=8

5 0

3 years ago

Which sentence uses coordinate adjectives?

Salsk061 [2.6K]

The correct answer should be A) because the adjectives are water and ice and they're describing the glass.

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3 years ago

Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items,

Ivanshal [37]

Answer:

77.64% probability that there will be 0 or 1 defects in a sample of 6.

Step-by-step explanation:

For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The true proportion of defects is 0.15

This means that $p = 0.15$

Sample of 6:

This means that $n = 6$

What is the probability that there will be 0 or 1 defects in a sample of 6?

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.15)^{0}.(0.85)^{6} = 0.3771$

$P(X = 1) = C_{6,1}.(0.15)^{1}.(0.85)^{5} = 0.3993$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3771 + 0.3993 = 0.7764$

77.64% probability that there will be 0 or 1 defects in a sample of 6.

5 0

3 years ago

Ir J() =<br> E and 9(1) = 2+3-<br> -s find f0-8

Ivan

Answer:

2456.8

Step-by-step explanation:

J=×

9×1=2+3'5

f=2456.8

7 0

3 years ago