Answer:
First, you add 11 to the other side of the equals sign. So it would be 2x=k+11. Now, you divide 2 from x and do the same on the other side of the equals sign. so x= k+11
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2
Step-by-step explanation:
Answer:
Step-by-step explanation:
pop 1 n₁ = 260, p₁ = 58% = 0.58
pop 2 n₂ = 260, p₂ = 8% = 0.08
Null hypothesis: p₁ ≤ p₂
Alternative hypothesis: p₁ > p₂
The test statistic : p₁-p₂ / √{p-sample (1 - p-sample) (1/n₁ + 1/n₂)}
where p-sample is sample proportion = p₁n₁ +p₂n₂ / n₁+n₂
Thus, p-sample = 0.58x260 +0.08x260 / 260+260 =150.8+20.8 / 520 = 171.6 / 520 = 0.33.
Thus, the test statistic is (0.58 - 0.08) / √[0.33 (1-0.33) (0.0038+0.0038)
= 0.5 / √[0.33(0.67) (0.0076)
= 0.5 / √0.00168036
= 0.5 / 0.04099
= 12.20
P = P(Z>12.20) = 1-P(Z≤12.20) at a significance level of 0.1= the p-value is less than the hypothesized thus, we have sufficient evidence to reject the null hypothesis and concluding that vinyl gloves have a greater virus leak than latex gloves.
Answer:
B. z Subscript alpha divided by 2 zα/2 = 1.96.
Step-by-step explanation:
We are given that we want to construct a confidence interval. For this, the summary statistics for randomly selected weights of newborn girls:
n = 236, 
= 30.3 hg, s = 7.2 hg. The confidence level is 95%.
As we can clearly see here that the population standard deviation is unknown and the sample size is also very large.
It has been stated that when the population standard deviation is unknown, we should use t-distribution but since the sample size is very large so we can use z distribution also as it is stated that at very large samples; the t-distribution corresponds to the z-distribution.
Here, 
= level of significance = 1 - 0.95 = 0.05 or 5%
= 0.025 or 2.5%
So, the value of 
in the z table is given as 1.96 with a 2.5% level of significance.
620*1.35=837 so 837ml is the answer
