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3 years ago

How would you set up part C to get the answer(answer if you can 60points)

Mathematics

1 answer:

pishuonlain [190]3 years ago

8 0

Answer:

Step-by-step explanation:27=3/2*10+12

27=30/2+12

27=15+12

27=27

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Help. I need to factor and solve using the quadratic formula -x^2+2x=7

aleksandrvk [35]

Answer:

Irreducible factorization

Step-by-step explanation:

7 0

3 years ago

2y to the power of 2x - 3xz = ?

MrRissso [65]

Answer:

x•(2xy-3z)

Step-by-step explanation:

2x²y -3xz== x(2xy-3z)

6 0

4 years ago

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 1 unit

padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

$\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.$

3. We write the matrix form as Ax=d

$A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)$

$x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)$

$A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

With this formula the solution of x is $x=\frac{d}{A}$ or $x=A^{-1}d$

4. We will find the inverse matrix $A^{-1}$ using the formula:

$A^{-1} = \frac{1}{detA} (C_{A})^{T}$

a. det A

$det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3$

b. $(C_{A})^{T}$

$C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)$

$C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

c. $A^{-1}$

$A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

5. As $x=\frac{d}{A}$ or $x=A^{-1}d$ , the solution of x is:

$x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)$

$X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]$

Therefore:

a= 350 Transistors

b=0 Resistors

c=340 Computer chips

4 0

3 years ago

Points A,M and P are collinear with M in between A and P. If AP=29, AM =5x-3 and MP=8x+6, what does MP=?

charle [14.2K]

The length of MP is 22 units.

<h3>What is a Line Segment?</h3>

A line segment is defined as a measured path between two places. Line segments can make up any polygon's sides because they have a set length.

The figure is given below shows a line segment AP, where the length of line segment AP refers to the distance between its endpoints, A and P.

Given that Points A, M and P are collinear with M in between A and P.

AP=29, AM =5x-3 and MP=8x+6,

A______________M______________P

⇒ AP = AM + MP

Substitute the values of AP = 29, AM =5x-3 and MP=8x+6,

⇒ 29 = 5x - 3 + 8x+6,

Rearranging the terms in the above equation,

⇒ 5x + 8x = 29 + 3 - 6

⇒ 13x = 26,

⇒ x = 26/13,

⇒ x = 2

So MP = 8x+6

Substitute the value of x = 2 in the above equation,

⇒ MP = 8(2) + 6

⇒ MP = 22

Hence, the length of MP is 22 units.

Learn more about the line segment here:

brainly.com/question/25727583

#SPJ1

6 0

2 years ago

0=(x+3)(x-2)?????????

VLD [36.1K]

Answer:

x=-3, x=2 or x=3,2

4 0

4 years ago