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iogann1982 [59]
3 years ago
9

I need help desperitly

Mathematics
1 answer:
topjm [15]3 years ago
8 0
Number one is 12. There is 12 cubes.
You might be interested in
Find the smallest value of k such that the LCM of<br> k and 6 is 60
Advocard [28]

Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60  is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.

Hence, the smallest value of k is 10.

5 0
3 years ago
Easy math for u trust me
iogann1982 [59]
Answer:
6457 + 7925 = 14382
5 0
2 years ago
Read 2 more answers
What is the surface area of the cylinder?
Murrr4er [49]
The answer is B. 128.1
7 0
3 years ago
What is the answer ?
kifflom [539]
The system of inequalities is the following:

i) <span>y ≤ –0.75x
ii)</span><span>y ≤ 3x – 2

since </span>0.75= \frac{75}{100}= \frac{3}{4}, we can write the system again as 

i) y \leq - \frac{3}{4}x
ii) y  \leq 3x-2

Whenever we are asked to sketch the solution of a system of linear  inequalities, we:

1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.


A.

to draw the line y =- \frac{3}{4}x

consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which y =- \frac{3}{4}x hold.

since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).

In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.

For (x, y)=(1, 1) the inequality y  \leq - \frac{3}{4}x, does not hold because 

1 \leq - \frac{3}{4}*1= -\frac{3}{4} is not true,

this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.


B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2, 

we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.

after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.

for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold

because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.


The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.

the lines intersect at (0.533, -0.4) because:

–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533

for x=0.533, y=3x-2=3(0.533)-2=-0.4

Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants

8 0
3 years ago
So i have a pic i need 1a plz i am giving a bunch of my points plz give it real asap
Alex_Xolod [135]

Answer:

3x - (15 x 3) = 90

or

3x - 45 = 90

Explanation:

there are 3 boxes. We don't know how many are in them yet, so we write this as 3x. However, we know that we give away 15 to 3 different teachers. 15 x 3 = 45

Therefore the first part is 3x - 45

We also know that in the end we have 90 left.

So our final equation is:

3x - 45 = 90

6 0
3 years ago
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