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denis-greek [22]
3 years ago
10

Which program can damage your computer? can cause damage to my computer.

Computers and Technology
2 answers:
Crazy boy [7]3 years ago
4 0

Answer:

Any virus that is a worm or a trojan will attack your computer

Explanation:

svetlana [45]3 years ago
3 0

Answer:

Malware is designed to cause damage to a stand alone computer or a networked pc. So wherever a malware term is used it means a program which is designed to damage your computer it may be a virus, worm or Trojan.

Explanation:

You might be interested in
how to create use an array of Course objects instead of individual objects like course 1, course 2, etc
AURORKA [14]

Answer:

To save the course object instances in an array, use;

Course[] courses = new Course[7];

courses[0] = new Course("IT 145");

courses[1] = new Course("IT 200");

courses[2] = new Course("IT 201");

courses[3] = new Course("IT 270");

courses[4] = new Course("IT 315");

courses[5] = new Course("IT 328");

courses[6] = new Course("IT 330");

Explanation:

The java statement above assigns an array of size 7 with the course class constructor, then order courses are assigned to the respective indexes of the new array.

3 0
3 years ago
Write a program which asks the user to enter N numbers. The program will print out their average. Try your program with the foll
Likurg_2 [28]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

int n;

double average,sum=0,x;

cout<<"enter the Value of N:";

// read the value of N

cin>>n;

cout<<"enter "<<n<<" Numbers:";

// read n Numbers

for(int a=0;a<n;a++)

{

   cin>>x;

   // calculate total sum of all numbers

   sum=sum+x;

}

// calculate average

average=sum/n;

// print average

cout<<"average of "<<n<<" Numbers is: "<<average<<endl;

return 0;

}

Explanation:

Read the total number from user i.e "n".Then read "n" numbers from user with for loop and sum them all.Find there average by dividing the sum with n.And print the average.

Output:

enter the Value of N:5

enter 5 Numbers:20.5 19.7 21.3 18.6 22.1

average of 5 Numbers is: 20.44

7 0
4 years ago
Any file that contains data but not instructions for your computer is not considered software
DIA [1.3K]
True. 

But then again, partly false. A .deb file (Debian, Ubuntu Linux) contains data, but that data needs to be installed and marked executable to make the software.

But i would still say true.
5 0
3 years ago
Which of the following is applicable during a hostile act:
Elanso [62]
Your question has been up too long, a moderator may have to delete it.
we will contact moderators to find your question and remove it, and hopefully, they will refund the points, which is not up to me.
<span>thank you for using brainly.</span>
3 0
3 years ago
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
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