Job A pays $19.94 per hour. Job B pays $18.76 per hour, and this job has health

a store is having a 30% off sale on their whole store a sweater costs 245$ what will it cost after the 30% was taken off

pentagon [3]

Answer:

$171.50

Step-by-step explanation:

8 0

3 years ago

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Given the point and slope write the equation of the line (-4, 0); slope = 1/2

Gwar [14]

Answer:

The equation of the line will be:

$y=\frac{1}{2}x+2$

Step-by-step explanation:

Given the point

(-4, 0)

slope = m = 1/2

As the equation of a line in slope-intercept form is

$y-y_1=m\left(x-x_1\right)$

where m is the slope

substituting the values m = 1/2 and the point (-4, 0)

$y-y_1=m\left(x-x_1\right)$

$y-0=\frac{1}{2}\left(x-\left(-4\right)\right)$

$y=\frac{1}{2}\left(x-\left(-4\right)\right)$

$y=\frac{1}{2}\left(x+4\right)$

$y=\frac{1}{2}x+\frac{4}{2}$

$y=\frac{1}{2}x+2$

Therefore, the equation of the line will be:

$y=\frac{1}{2}x+2$

3 0

3 years ago

What is the ninth term of the arithmetic sequence defined by the rule below?

Leokris [45]

Answer:

A

Step-by-step explanation:

Substitute n = 9 into the nth term rule

A(9) = - 15 + 2(9 - 1) = - 15 + 2(8) = - 15 + 16 = 1 → A

6 0

3 years ago

A commuter has to cross a train track each day on the way to work. The probability of having to wait for a train is .2. If she h

Anni [7]

Answer:

21 minutes

Step-by-step explanation:

Her expected commute time is given by the probability of having to wait for the train (0.2) multiplied by the commute time in this scenario (25 min), added to the probability of not having to wait for the train (1 - 0.2) multiplied by the commute time in this scenario (20 min). The expected commute time is:

$E(X) = 0.2*25+(1-0.2)*20\\E(X) = 21\ minutes$

Her expected commute time is 21 minutes.

7 0

3 years ago

2. Create an estimated probability distribution for the time teens spend texting.

Furkat [3]

Answer:

Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

Frequency* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

Frequency 170 82 220 153 92 58 40 15 12 18 10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

Total Sample Size = 870

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)= $\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}$

For Example:

Estimated probability distribution that teens spend 0 hours texting= $\frac{170}{870} =0.20$

Similarly

Estimated probability distribution that teens spend 0.5 hours= $\frac{82}{870} =0.09$

Using the same formula we get:

Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

Frequency* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01

(Note: Frequency* is the estimated probability distribution)

4 0

3 years ago

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