2 years ago

As the sun sets on the horizon, its rays are ____________ by the ocean water.

Physics

1 answer:

sasho [114]2 years ago

7 0

Ultraviolet Ray and red light sun sets on the horizon

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A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon

mylen [45]

Answer:

Impulse = change in momentum w bounce

There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.

7 0

2 years ago

A student placed 700g of water at 28° c in the freezer.after 6 minutes and 15 seconds the water was transformed to ice.

Maru [420]

Answer:

is this the full questions

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3 years ago

An interstellar space probe is launched from Earth. After a brief period of acceleration it moves with a constant velocity, 70.0

sleet_krkn [62]

Answer:

22.26 years

, 15.585 light years , 11.13 light years

Explanation:

$t' = t/(\sqrt{1-(v/(c*v)/c)}$

= $15.9/\sqrt{(1-0.7*0.7)}$

= 22.26 years

0.7*c*22.26 years

=15.585 light years

0.7*c*15.9

=11.13 light years

3 0

3 years ago

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o

Leya [2.2K]

Answer:
frequency = 5.52 * 10² Hz

Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength

We are given that:
velocity = 331 m/sec
wavelength = 0.6 m

Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
frequency = 331 / 0.6
frequency = 5.52 * 10² Hz

Hope this helps :)

4 0

2 years ago

A car is traveling north at 17.7 m/s . After 6 it’s velocity is 141 in the same direction. Find the magnitude and direction of t

Furkat [3]

By equation of motion we have v = u + at

Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration

Here v = 141 m/s, u = 17.7 m/s and t = 6 s

On substitution we will get

141 = 17.7+ 6a

So, a = (141-17.7)/6 = 20. 55 m/ $s^{2}$

Aceeleration = 20. 55 m/ $s^{2}$ along north direction.

3 0

3 years ago