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stellarik [79]
3 years ago
15

As the sun sets on the horizon, its rays are ____________ by the ocean water.

Physics
1 answer:
sasho [114]3 years ago
7 0
Ultraviolet Ray and red light sun sets on the horizon
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What inductance l would be needed to store energy e=3.0kwh (kilowatt-hours) in a coil carrying current i=300a?
myrzilka [38]

The formula for the energy stored in the magnetic field of an inductor is:

                      E  =  (1/2) (inductance) (current)²  .

In the present situation:

Energy = (3 kilo-watt-hour) x (1,000 / kilo) x (joule/watt-sec) x (3,600 sec/hr)

           =  (3 · 1000 · 3,600)  (kilo·watt·hr·joule·sec / kilo·watt·sec·hr)

           =      1.08 x 10⁷ joules .

Now to find the inductance:  

                   E  =  (1/2) (inductance) (current)² 

       (1.08 x 10⁷ joules) = (1/2) (inductance) (300 Amp)²

           (2.16 x10⁷ joules) =  (inductance) (300 Amp)²

             Inductance =  (2.16 x10⁷ joules) / (300 Amp)²

                              =   2.16 x10⁷ / 90,000        Henrys

                           I get        240 Henrys .

This is a big inductance.  Possibly the size of your house.
To get a big inductance, you want to wind the coil
  with a huge number of turns of very fine wire, in
  a small space.
In this case, however, if you plan on running 300A through
  your coil, it'll have to be wound with a very thick conductor ...
  like maybe 1/4-inch solid copper wire, or even copper tubing,
You have competing requirements.
There are cheaper, easier, better ways to store 3 kWh of energy.
In fact, a quick back-of-the-napkin calculation says that
  3 or 4 car batteries will do the job nicely.
5 0
3 years ago
Can solar energy turn into sunlight?
iragen [17]

Nothing has to turn.

Sunlight <u><em>IS</em></u> solar energy !


4 0
3 years ago
A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend
telo118 [61]

Answer:

A. Ein = 8.05*10^-4 V/m

B. Clockwise sense

Explanation:

A. the magnitude of the electric field induced in the ring is obtaind by using the following formula:

\int E_{in} \cdot ds=-\frac{d\Phi_B}{dt}            (1)

Ein: induced electric field

ds: differential of a path of the ring

ФB: magnetic flux in the ring

The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):

\int E_{in}ds=E_{in}(2\pi r)=-A\frac{dB}{dt}\\\\E_{in}=-\frac{A}{2\pi r}\frac{dB}{dt}   (2)

dB/dt = -0.280T/s     (it is decreasing)

A: area of the ring = π(r/2)^2= (π/4) r^2

r: radius of the ring = 4.60/2 = 2.30 cm

Then, you replace the values of all variables in the equation (2):

E_{in}=-\frac{(\pi/4)r^2}{2\pi r}\frac{dB}{dt}=\frac{r}{8}\frac{dB}{dt}\\\\E_{in}=-\frac{0.0230m}{8}(-0.280T)=8.05*10^{-4}\frac{V}{m}

hence, the induced electric field is 8.05*10^-4 V/m

B. The induced current in the ring produced a magnetic field that is opposite to the magnetic field of the magnet. The, in this case you have that the induced current is in a clockwise sense.

6 0
4 years ago
HELLLLLLPPPPP!!!!!!!!!!!!!!!!!!!!! I will give brainliest
Misha Larkins [42]

Answer:

d

Explanation:

4 0
3 years ago
mr. tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space,
marishachu [46]
Based on the description, it will be most likely that he believes in Oscillating model (also known as Cyclic model) of the universe

Based on this model, the gravitational force will prevent further expansion by pulling back the matters and undergo a bounce

hope this helps
8 0
3 years ago
Read 2 more answers
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