Answer:
Amount of energy required to change the 1kg of a substance without changing its temperature.
Answer:
Q = 2687130 J
Explanation:
m = mass of block of ice = 5 kg
= Initial temperature of ice block = - 27 °C
= final temperature of water = 35 °C
= specific heat of ice = 2108 J/(Kg °C)
= Latent heat of fusion of ice = 334000 J/kg
= specific heat of water = 4186 J/(Kg °C)
Heat added is given as



Answer:
Explanation:
Energy of system of charges
= k q₁q₂ / r₁₂ + k q₁q₃ / r₁₃ + k q₃q₂ / r₃₂
q₁ , q₂ and q₃ are charges and r₁₂ , r₁₃ , r₃₂ are densities between them
9 x 10⁹ ( 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 )
= 9 x 10⁹ x 3 x 16 x 10⁻¹²
= 432 x 10⁻³
= .432 J .
The freshwater reservoirs on earth are ranked by volume, with the one with the biggest volume at the top is-
1. ice caps; 2. groundwater; 3. lakes; 4. rivers.
<h3>Explain the freshwater reservoirs on earth?</h3>
The atmosphere, the earth's surface, and the earth's interior are the three main locations where water can be kept.
- Oceans, glacier ice, underground, lakes, soil humidity, living organisms, atmospheric atmosphere, and rivers are examples of these reservoirs, which are used to store water.
- There is an estimated 1.386 billion km3 (330 million cubic miles) of water on Earth, of which 97.5% is salt water and 2.5% is fresh water.
- Only 0.3% of a fresh water is liquid at the surface.
- More than 70% of freshwater is utilized for agriculture in the majority of the world's areas.
- An estimated 50% increase in agricultural output and a 15% increase in water flows are needed by 2050 to feed a globe of 9 billion people.
Thus, the freshwater reservoirs on earth are ranked by volume, with the one with the biggest volume at the top is-
- 1. ice caps
- 2. groundwater
- 3. lakes
- 4. rivers
To know more about the freshwater reservoirs, here
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Answer:
the sphere
Explanation:
From the given information,
A free flow body diagrammatic expression for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane can be seen in the image attached below.
From the diagram;
The Normal force mgsinθ - Friction force F = mass m × acceleration a
Meanwhile; the frictional force

where
in a rolling motion
Then;

∴
The Normal force mgsinθ - F = m × a can be re-written as:

making a the subject of the formula, we have:

Similarly;
I = mk² in which k is the radius of gyration
∴
replacing I = mk² into the above equation , we have:

where;
the uniform disk
the uniform sphere
∴


We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.