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madreJ [45]
3 years ago
11

A bicycle pedal is pushed straight downwards by a foot with a 33 Newton force. The shaft of the pedal is 20 cm long. If the shaf

t is π/5π/5 radians past horizontal, what is the magnitude of the torque about the point where the shaft is attached to the bicycle?
Physics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm

Explanation:

The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:

T = d * Fp

Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:

Fp = F*sin(a)

Replacing the values for the force and the angle:

Fp = 33N*sin(π/5)  = 33N * 0.011 = 0.363 N

Taking the distance in meters:

T = 0.2m * 0.363 N = 0.063 Nm

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Answer:

The force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.

Explanation:

To force is given by:

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Where:

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By entering the above values into equation (1) we have:

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Therefore, the force on one square foot of the earth’s surface caused by the atmosphere is 101.4 kN.

I hope it helps you!

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