Question

A bicycle pedal is pushed straight downwards by a foot with a 33 Newton force. The shaft of the pedal is 20 cm long. If the shaft is π/5π/5 radians past horizontal, what is the magnitude of the torque about the point where the shaft is attached to the bicycle?

Answer 1

Answer:

The magnitud of the torque doing by the foot at the point where the shaft is attached is 0.063 Nm

Explanation:

The torque is obtained by multiplying the longitude from the shaft attached point to force acting point by the force perpendicular component:

T = d * Fp

Notice that the perpindicular component is the total force magnitud times the sino of the angle respect the horizontal:

Fp = F*sin(a)

Replacing the values for the force and the angle:

Fp = 33N*sin(π/5)  = 33N * 0.011 = 0.363 N

Taking the distance in meters:

T = 0.2m * 0.363 N = 0.063 Nm