If you are asking for the weight then the formula is F=mg where f is weight m is mass and g is acceleration due to gravity.m=52kg and g=9.8m/s2(the gravity of earth)
F=52*9.8=509.6
therefore the weight of the object is 509.6N
Answer:
The angular speed is 
Explanation:
From the question we are told that
The time taken is 
The number of somersaults is n = 1.5
The total angular displacement during the somersault is mathematically represented as

substituting values


The angular speed is mathematically represented as

substituting values


Sound is a longitudinal wave.
Solution :
Acceleration due to gravity of the earth, g 

Acceleration due to gravity at 1000 km depths is :




= 8.23 m/s
Acceleration due to gravity at 2000 km depths is :




= 6.73 m/s
Acceleration due to gravity at 3000 km depths is :



= 5.18 m/s
Acceleration due to gravity at 4000 km depths is :




= 3.64 m/s
By what i know i think that the answer would be A a homogeneous mixture.