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Rzqust [24]
3 years ago
11

Which structures protect the cell? Check all that apply.

Physics
2 answers:
MAXImum [283]3 years ago
8 0

Answer:

cell wall and cell membrane

zimovet [89]3 years ago
6 0

Answer:

Cell wall and Cell membrane.

Explanation:

The cell membrane controls what goes in and out of the cell

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A wave has a length of 8 meters and a speed of 32 meters per second. What is the frequency of the wave
Naddika [18.5K]

Answer:

The frequency of wave is 4 hertz.

Explanation:

Given,

wave length = 8m

speed of sound ( v) = 32 m/s

frequency ( f) = ?

we know,

v = f × lambda

or, 32 = f × 8

or, f = 32/8

or, f = 4 Hertz.

5 0
3 years ago
A student examines the effect of the number of D batteries in a closed circuit on the brightness of a light bulb. In the experim
salantis [7]

The correct answer is the Type of batteries

Explanation:

In an experiment, it is normal the researcher modifies one variable, in this case, the number of batteries (independent variable), and this variable affects the variable tested, in this case, the brightness of the bulb (dependent variable).

However, other factors or variables should be constant to guarantee the results are reliable. In this context, one factor that the student should keep constant is the type of batteries he uses because this is not one of the main variables and therefore it is not expected he changes this on purpose or this is affected by other variables. Moreover, by making any change the experiment can be negatively affected. For example, batteries might differ in their power capacity this can affect the brightness of the bulbs.

3 0
3 years ago
What causes an object to slow down or speed up?​
Arisa [49]

Answer:

Unbalanced forces

Explanation:

Unbalanced forces acting on an object can change the object's speed, causing it to speed up or slow down.

6 0
3 years ago
Read 2 more answers
Another name for continuous uniform circular motion is___?
VikaD [51]
I think the answer is constant
5 0
3 years ago
Suppose that a 102.5 kg football player running at 8.5 m/s catches a 0.47 kg ball moving at a speed of 22.5 m/s with his feet of
nadya68 [22]

Answer:

a) v=8.564\ m.s^{-1}

b) \Delta KE=45.76\ J

c) v=8.358\ m.s^{-1}

d) \Delta KE=225.24\ J

Explanation:

Given:

mass of the player, m_p=102.5\ kg

mass of the ball, m_b=0.47\ kg

initial velocity of the player, v_p=8.5\ m.s^{-1}

initial velocity of the ball, v_b=22.5\ m.s^{-1}

a)

<u>Case:</u> When the player and the ball are moving in the same direction.

m_t.v=m_p.v_p+m_b.v_b

where:

m_t=total mass after the player catches the ball

v = final velocity of the system

v=\frac{102.5\times 8.5+0.47\times 22.5}{(102.5+0.47)}

v=8.564\ m.s^{-1}

b)

Initial kinetic energy of the system:

KE_i=\frac{1}{2} [m_p.v_p^2+m_b.v_b^2]

KE_i=\frac{1}{2} [102.5\times 8.5^2+0.47\times 22.5^2]

KE_i=3821.78\ J

Final kinetic energy of the system:

KE_f=\frac{1}{2} m_t.v^2

KE_f=\frac{1}{2}\times 102.97\times 8.564^2

KE_f=3776.02\ J

∴Change in kinetic energy

\Delta KE=KE_i-KE_f

\Delta KE=3821.78-3776.02

\Delta KE=45.76\ J

c)

<u>Case:</u> When the player and the ball are moving in the opposite direction.

m_t.v=m_p.v_p-m_b.v_b

v=\frac{102.5\times 8.5-0.47\times 22.5}{(102.5+0.47)}

v=8.358\ m.s^{-1}

d)

Final kinetic energy in this case:

KE_f=\frac{1}{2} m_t.v^2

KE_f=0.5\times 102.97\times 8.358^2

KE_f=3596.54\ J

∴Change in kinetic energy:

\Delta KE=KE_i-KE_f

\Delta KE=3821.78-3596.54

\Delta KE=225.24\ J

3 0
3 years ago
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