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SVEN [57.7K]
3 years ago
5

Can someone plz help me!!!

Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
6√25, ∛27, √64, ∛64

6*5, 3, 8, 4

30, 3, 8, 4

∛64 > ∛27> √ 64 > 6√25
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Solve for y.<br> 2x-3y=9
cluponka [151]

Answer:

y = 2/3x - 3

Step-by-step explanation:

Step 1: Write equation

2x - 3y = 9

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -3y = 9 - 2x
  2. Divide both sides by -3: y = -3 + 2/3x
  3. Rewrite: y = 2/3x - 3
6 0
3 years ago
F(x) = 2x2 – 4x – 3
Elanso [62]
Mica should have added 2 to 3 instead of 1
7 0
3 years ago
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Identify the coordinates of the vertex of f(x) = (x – 3)2 + 14, and identify whether it's an absolute minimum or absolute maximu
BlackZzzverrR [31]

Answer:

The answer is option B.

Hope this helps.

7 0
3 years ago
What properties makes the equation ture?
Oksi-84 [34.3K]

Answer:

A.2z+5=5+2z

Associative properties

Distributive properties

Commutative properties

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5 0
3 years ago
A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st
SpyIntel [72]

Answer:  15.3\pm0.198

OR

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval(\mu) is given by :-

\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}

, where n is the sample size

s = sample standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha .

Given : Confidence level = 95% = 0.95

Significance level = \alpha=1-0.95=0.05

s= 1.6

\overline{x}=15.3

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , \sigma=1.6

By standard normal  distribution table ,

Two tailed z-value for Significance level of 0.05 :

z_{\alpha/2}=z_{0.025}=1.96

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

5 0
3 years ago
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