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3 years ago

Name the points which satisfy the conditions.

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

Answer:

The points C, D, E F , H and G all have POSITIVE X- VALUES.

Step-by-step explanation:

The points which lie either in 1st Quadrant, 4th Quadrant or on the positive X - axis ,and Y axis they have positive x value.

Now, here:

C lies on Origin (0,0) Hence, a positive X- value.

D and E lie in Quadrant 1 . Hence, a positive X- value.

F lies on X-axis. Hence, a positive X- value.

A and B lie in Quadrant 2 . Hence, a negative X- value.

G lies in Quadrant 4. Hence, a positive X- value.

H lies on Y-axis. Hence, a positive X- value = 0

Hence, the points C, D, E F , Hand G all have POSITIVE X- VALUES.

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Factor out the GCF of 64−32x

Mekhanik [1.2K]

Answer: 32

Step-by-step explanation:

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3 years ago

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A41.0m guy wire is attached to the top of a 32.8 m antenna and to a point on the ground. How far is the point on the ground from

Setler79 [48]

Answer:

Step-by-step explanation:

A right angle triangle is formed.

The length of the guy wire represents the hypotenuse of the right angle triangle.

The height of the antenna represents the opposite side of the right angle triangle.

The distance, h from base of the antenna to the point on the ground to which the antenna is attached represents the adjacent side of the triangle.

To determine h, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

41² = 32.8² + h²

1681 = 1075.84 + h²

h² = 1681 - 1075.84 = 605.16

h = √605.16

h = 24.6 m

To determine the angle θ that the wire makes with the ground, we would apply the the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos θ = 24.6/41 = 0.6

θ = Cos^-1(0.6)

θ = 53.1°

7 0

4 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago

Helppppppppppppppp !!!!

Len [333]

Answer:

Angle(APR) = 43

x = 21.5

Step-by-step explanation:

The given angles are complementary :

So APR + RPW = 90

APR = 43

2x = 43

x = 21.5

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3 years ago

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Kevin ran 6/7 miles and his brother james ran 10 miles. How many miles did the two of them ran.

masya89 [10]

Answer:

16.7 miles

Step-by-step explanation:

6.7+10=16.7

The two of them ran 16.7 miles.

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3 years ago