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jekas [21]
3 years ago
11

Write a real world problem that could be solved by using the equation

ula1" title="3x-25=125" alt="3x-25=125" align="absmiddle" class="latex-formula">. Then solve the equation...
Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

x=50

See below for word problem.

Step-by-step explanation:

While shopping, you spend $125 before tax. You buy 3 dresses at the same price each and receive a $25 discount. How much is the price of each dress?

3x-25=125

3x=125+25

3x=150

x=50

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3 years ago
Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni
dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})

It is provided that, Renee recognizes that 7 and \frac{1}{7} are reciprocals, so she would like to find their product before she multiplies by \frac{13}{29}.

The associative property of multiplication states that:

a\times b\times c=(a\times b)\times c=a\times (b\times c)

The commutative property of multiplication states that:

a\times b\times c=a\times c\times b=c\times a\times b

The distributive property of multiplication states that:

a\cdot (b+c)=a\cdot b+a\cdot c

The identity property of multiplication states that:

a\times 1=a\\b\times 1=b

So, Renee should use the commutative property of multiplication to find the product of 7 and \frac{1}{7},

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}

Thus, the correct option is commutative property.

5 0
3 years ago
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