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3 years ago

The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.

Mathematics

2 answers:

andrey2020 [161]3 years ago

7 0

Answer:

14 home runs

Step-by-step explanation:

This is basically a subtraction problem.

So the maximum number is 60 home runs in 1927.

The minimum number is 46 home runs in 1929.

So you subtract these 2 values.

60 - 46

= 14

So the maximum number exceed the minimum number with 14 home runs as the difference.

kumpel [21]3 years ago

5 0

Answer:

Step-by-step explanation:

max no. of HRs is 60 in 1927

min no. of HRs is 46 in 1929

max exceeds min by 60-46 = 14

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The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.

The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.