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Vesnalui [34]
3 years ago
12

A line passes through (-1,5) and (1,3) what is the equation of the line

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

y = -x + 4

Step-by-step explanation:

(-1,5)...x1 = -1 and y1 = 5

(1,3)....x2 = 1 and y2 = 3

slope(m) = (y2 - y1) / (x2 - x1) = (3 - 5) / (1 - (-1) = -2 / (1 + 1) = -2/2 = -1

y = mx + b

slope(m) = -1

u can use either of ur points...I will use (1,3)...x = 1 and y = 3

now we sub and find b, the y int

3 = -1(1) + b

3 = -1 + b

3 + 1 = b

4 = b

ur equation is : y = -x + 4 <===

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Answer:

1. x = 8

2. x = 3

3. x = 25

4. x = 6

5. x = 11

6. x = 3

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Step-by-step explanation:

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2. 34x + 5 = 35x + 2

Step 1: Subtract 35x from both sides.

34x + 5 − 35x = 35x + 2 − 35x

−x + 5 = 2

Step 2: Subtract 5 from both sides.

−x + 5 − 5 = 2 − 5

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Step 1: Flip the equation.

2x + 65 = 115

Step 2: Subtract 65 from both sides.

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2x/2 = 50/2

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84 + 16x = 180

84 - 84 + 16x = 180 - 84

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5.

2(3x − 10) = 46

Step 1: Simplify both sides of the equation.

2(3x − 10) = 46

(2)(3x) + (2)(−10 )= 46(Distribute)

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6x − 20 = 46

Step 2: Add 20 to both sides.

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Step 1: Simplify both sides of the equation.

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Step 2: Flip the equation.

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Step 2: Add 12 to both sides.

4x−12+12=28+12

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Step 3: Divide both sides by 4.

4x/4 = 40/4

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