Question

Which method is most efficient method to use to solve 2x^2+4x-7=0

Answer 1

Answer:

Use the quadratic formula

Step-by-step explanation:

Use the quadratic formula

For a quadratic function of the form:

$ax ^ 2 + bx + c$

Where a, b and c are the real coefficients of the polynomial

Then, for

$2x^2+4x-7=0\\a = 2\\b = 4\\c = -7$

The solutions are:

$x_1 = \frac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_2 = \frac{-b-\sqrt{b^2-4ac}}{2a}$

$x_1 = \frac{-4+\sqrt{4^2-4(2)(-7)}}{2(2)}\\\\x_2 = \frac{-4-\sqrt{4^2-4(2)(-7)}}{2(2)}\\\\x_1 = \frac{-2+3\sqrt{2}}{2}\\\\x_2 = \frac{-2-3\sqrt{2}}{2}$