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andrey2020 [161]
3 years ago
5

Which of the following hypotheses is a null hypothesis? Group of answer choices There is no difference in the monthly grocery bi

lls of families with one child and families with two children Grocery bills vary according to the number of meals eaten outside the home Families with two children have significantly higher grocery bills than families with just one child There is a relationship between grocery bills and the number of people in a household The mean age in a household is predictive of the amount of money sent on food each month
Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

The following hypotheses is a null hypothesis:

There is no difference in the monthly grocery bills of families with one child and families with two children.

Step-by-step explanation:

In inferential statistics, it is a null hypothesis because it is assuming to be true until evidence indicates otherwise, it is a general position without relationship between the two measured phenomena (one child and two children), testing (accepting, approving, rejecting, or disproving), concluding that  there are not reasons for believing that there is a relationship between two phenomena  and gives precise criteria for rejecting the null hypothesis within a confidence level.

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PLEASE HELP ASAP
Svetlanka [38]
Members: 3x + 20
Nonmembers: 5x
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5 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
What is the slope of this table<br> х<br> у<br> 0<br> 1<br> 1<br> 4<br> 2<br> 4<br> 7<br> 13<br> 16
Jobisdone [24]

Answer:

THE ANSWER IS 222

Step-by-step explanation:

5 0
3 years ago
Write an<br> expression that is equivalent to -0.5(20f – 16).
pashok25 [27]

Answer:

  • - 10f + 8

Step-by-step explanation:

<u>Given expression:</u>

  • - 0.5(20f - 16)

<u>Distribute and simplify:</u>

  • -0.5(20f) - 0.5(- 16) =
  • - 10f + 8
6 0
3 years ago
Read 2 more answers
Which of these prices is lower than 5 for $3.00
Serga [27]

Where's the options?

7 0
3 years ago
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