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frutty [35]
3 years ago
10

Marley loves to draw and color. She bought 6 boxes of crayons. There are 8 crayons in each box. What is the total number of cray

ons Marley bought? What operation did you use to find your answer? Be sure to write your answer in a complete sentence.
Mathematics
2 answers:
Tanzania [10]3 years ago
7 0

Answer:

48 crayons

Step-by-step explanation:

There are 6 boxes total, each with 8 crayons in them. Notice that if you would count all the crayons, you would add 8 to the total number of crayons each time you counted a box. There are 6 boxes, so that would be equivalent to adding 8 a total of six times. You would use multiplication: 6 x 8 which is 48.

Lera25 [3.4K]3 years ago
3 0

Answer:

marley has 48 crayons he bought

step by step equation:

6 times 8 =48

you use multiplication to answer this question

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Record the data in a table with the rows representing the type of music and the columns representing the weeks.
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Answer:

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Step-by-step explanation:

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HELP! Simplify: -6 (5/3x+4)<br> A) -10x-24. B) -10x-24. C) -10x+4. D) -10x-4.
pashok25 [27]

Answer:

D) -10x-4

Step-by-step explanation:

−6(5/3x+4)

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6 0
3 years ago
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X(x) + 12x + 21 = 0 factor
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It is not factorable. Factors of 21 are. 21 and 1
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Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ &gt; 0.
Ket [755]
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The requirement that \tan{\theta}\ \textgreater \ 0 eliminates -1/6 from being another solution.
6 0
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Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

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Given that 0 \le x < 2\pi,

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x = 0 or x = \pi.

8 0
3 years ago
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