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viktelen [127]
3 years ago
13

Solve, using the substitution method.

Mathematics
1 answer:
inna [77]3 years ago
8 0
Y - 2x = 8 . . . . (1)
16 + 4x = 2y . . (2)

From (1), y = 2x + 8 . . . (3)

Putting (3) into (2) gives
16 + 4x = 2(2x + 8) = 4x + 16
0 = 0

Therefore, there are infinite number of solutions.
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A glazier is setting supports in parallel segments to prevent glass breakage during storms. What are the values of x and y? Just
lara [203]

Answer:

m∠y=50°

m∠x=50°

Step-by-step explanation:

we know that

The angles in matching corners are called <u><em>corresponding angles</em></u>. When the two lines are parallel Corresponding Angles are equal

so

m∠y=50° -----> by corresponding angles

and

The angles that are formed on opposite sides of the transversal and inside the two lines are <u><em>alternate interior angles</em></u>. When the lines are parallel, the alternate interior angles are equal.

so

m∠x=m∠y -----> by alternate interior angles

so

m∠x=50°

therefore

m∠y=50°

m∠x=50°

5 0
4 years ago
Red bricks and grey bricks were used to build a decorative wall. The number of red bricks divided by number of grey bricks was 5
azamat
Red bricks : Grey bricks
        5        :            2

Total parts = 5 + 2 = 7

7 parts = 224
-----------------------
Find 1 part:
-----------------------
1 part = 234 ÷ 7
1 part = 32

-----------------------
Find 5 parts:
-----------------------
5 parts = 32 x 5 
5 parts = 160

----------------------------------------------
Answer: 160 Red bricks
----------------------------------------------
5 0
3 years ago
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
Identify the range of the following numbers 7 9 15
Deffense [45]
8 is your range, 15-7= 8.
7 0
3 years ago
Read 2 more answers
What is the unit rate of a 13-oz. package of pistachios that costs $5.99?
meriva
I believe it is $0.46...
8 0
3 years ago
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