Answer:
2KClO3 (s) → 2KCl (s) + 3O2 (g) (option C)
Explanation:
Step 1:
a. ___ KClO3 (s) → ___ KClO2 (s) + _____ O2 (g) __________
On the left side we have 3x O (in KClO3) and on the right side we have 4x O (2x in KClO2 and 2x in O2). To balance the amount of O on both sides, we have multiply KClO3 and KClO2 by 2.
2KClO3 (s) → 2KClO2 (s) + O2 (g)
This is not the reaction that occurs when KClO3 is heated
b. ___ KClO3 (s) ___ KClO (s) + _____ O2 (g) __________
This equation is already balanced
KClO3 (s) → KClO (s) + O2 (g)
c. ___ KClO3 (s) ___ KCl (s) + _____ O2 (g) __________
On the left side we have 3x O (in KClO3) and on the right side we have 2x O (in O2). To balance the amount of O on both sides, we have multiply KClO3 by 2 and O2 by 3.
On the left side we have 2x K (in 2KClO3) and on the right side we have 1x K (in KCl). To balance the amount of K on both sides, we have multiply KCl on the right side by 2.
2KClO3 (s) → 2KCl (s) + 3O2 (g)
When KClO3 is heated strongly, it breaks down, releasing oxygen gas and leaving behind a thermally stable (i.e., heat-insensitive) solid residue of an ionic potassium compound, as KCl
Option C is the correct answer
