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2 years ago

The number of molecules in 1.0 mole of h2o is the same as in one mole of o2.

Chemistry

1 answer:

Elis [28]2 years ago

8 0

True. The number of molecules in one mole of any substance is the same, the Avogadro number which is 6.022 * 10^23.

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A typical person has an average heart rate of 75.0 beats/min. Calculate the following a)How many beats does she have in 7.0 year

hram777 [196]

Let us first convert years to minute.

7 years * (365 days / year) * (24 hours / day) * (60 minutes / hour) = 3,679,200 minutes

a. beats = 75.0 beats/min * 3,679,200 minutes

beats = 275,940,000 beats

Since the original given is 7.0 years (2 significant figures), therefore:

beats = 270,000,000 beats

b beats = 75.0 beats/min * 3,679,200 minutes

beats = 275,940,000 beats

Since the original given is 7.000 years (4 significant figures), therefore:

<span>beats = 275,900,000 beats</span>

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3 years ago

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A soft drink contains 46 g of sugar(sucrose C12H22O11) how many sugar molecules are present?

professor190 [17]

8.092752363 ×10 to the power of 22

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3 years ago

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Ksivusya [100]

3 I’m pretty sure maybe

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2 years ago

What type of rock would be formed in this plant-rich swamp?

adell [148]

We are asked to identify what type of rock would be formed in a plant-rich swamp. We all know that plant dies and the remain leaves in the soil called peat. Temperature, pressure and heat causes the remains to submerged under the soil bed layer and converts it into a waxy substance called kerogen. Kerogen then mixes with the rock under the soil bed layer to create what is called an oil shale. Oil shale is somehow similar to a coal. Both creates an energy when ignited. Therefore the correct answer to the question being asked is COAL or Oil Shale.

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3 years ago

When methane ( CH4 ) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reac

slega [8]

<h2>Answer:</h2> $1.33*10^{-2}grams$

<h2>Explanations</h2>

The complete balanced equation for the given reaction is expressed as;

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Given the following parameters

Mass of CH4 = 5.90×10^−3 g = 0.0059grams

Determine the moles of methane

$\begin{gathered} moles\text{ of CH}_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CH}_4=\frac{0.0059}{16.04} \\ moles\text{ of CH}_4=0.000368moles \end{gathered}$

According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:

$\begin{gathered} moles\text{ of H}_2O=\frac{2}{1}\times0.000368 \\ moles\text{ of H}_2O=0.000736moles \end{gathered}$

Determine the mass of water produced

$\begin{gathered} Mass\text{ of H}_2O=moles\times molar\text{ mass} \\ Mass\text{ of H}_2O=0.000736\times18.02 \\ Mass\text{ of H}_2O=0.0133grams=1.33\times10^{-2}grams \end{gathered}$

Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams

5 0

1 year ago