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Mumz [18]
3 years ago
9

The number of molecules in 1.0 mole of h2o is the same as in one mole of o2.

Chemistry
1 answer:
Elis [28]3 years ago
8 0
True. The number of molecules in one mole of any substance is the same, the Avogadro number which is 6.022 * 10^23.
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Following reactions<br>FeSO4+KOH<br>​
prohojiy [21]

Explanation:

FeSO _{4} + \: KOH \: →K _{2}SO _{4} \:  +  \: Fe(OH) _{2}

5 0
3 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
3 years ago
How much heat (in kilojoules) is evolved or absorbed in the reaction of 1.90 g of na with h2o? 2na(s) 2h2o(l)→2naoh(aq) h2(
myrzilka [38]
Do you have a screen shot or picture of the problem?
3 0
3 years ago
Butanoic acid + 2 propanol
Talja [164]

Answer:

propyl butanoate

Explanation:

8 0
3 years ago
You need to use a dilute hydrochloric acid solution in an experiment. However, the only bottle of hydrochloric acid in your lab’
mr_godi [17]

The pH of the diluted HCl solution is 1.3.

Explanation:

Given:

The concentrated HCl solution of 8.0 M. The 1.5 mL of 8.0 M HCl is diluted with water to 250 mL volume.

To find:

The pH of the diluted HCl solution.

Solution

  • The concentration of the HCl solution before dilution = M_1=8.0 M
  • The volume of the HCl solution taken for dilution = V_1=1.5 ml
  • The concentration of the HCl solution after dilution =M_2=?
  • The volume of the HCl solution after dilution = V_2=250 mL

Using the Dilution equation:

M_1V_1=M_2V_2\\8.0M\times 1.5ml=M_2\times 250 mL\\M_2=\frac{8.0M\times 1.5ml}{250 mL}=0.048 M

The concentration of diluted HCl solution = 0.048 M

HCl(aq)\rightarrow H^+(aq)+Cl^-(aq)

In the 1 M solution of HCl, there are 1 M of hydrogen ion, then the concentration of hydrogen ions in 0.048 M of HCl will be:

[H^+]=1\times 0.048M=0.048 M

The pH of the diluted HCl solution :

pH=-\log [H^+]\\=-\log [0.048M]=1.18 \approx 1.3

The pH of the diluted HCl solution is 1.3.

Learn more about the dilution equation here:

brainly.com/question/24546169?referrer=searchResults

brainly.com/question/1199928?referrer=searchResults

4 0
3 years ago
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