Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer: x = 4.5
Step-by-step explanation:
1) Reorder the terms:
3x = -9 + 5x
2) Solving
3x = -9 + 5x
3) Solving for variable 'x'.
4) Move all terms containing x to the left, all other terms to the right.
5) Add '-5x' to each side of the equation.
3x + -5x = -9 + 5x + -5x
6) Combine like terms: 3x + -5x = -2x
-2x = -9 + 5x + -5x
7) Combine like terms: 5x + -5x = 0
-2x = -9 + 0
-2x = -9
8) Divide each side by '-2'.
x = 4.5
9) Simplifying
x = 4.5
Answer:
24+18x-36=216
-12+18x=216
18x=216+12
18x=228
x=228/18
x=30/3
Step-by-step explanation:
Answer:
The surrender of Detroit
Step-by-step explanation:
The other two were american victories, the surrender of Detroit was a Indian/British victory and an early one in the war
Each room would be 1 hour because it say that two rooms get painted in two hours <span />
