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3 years ago

If 2.9g of water is heated from 23.9C to 98.9C, how much heat (in calories) was added to the water?

Chemistry

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

Explanation:

we know that

ΔH=m C ΔT

where ΔH is the change in enthalpy (j)

m is the mass of the given substance which is water in this case

ΔT IS the change in temperature and c is the specific heat constant

we know that given mass=2.9 g

ΔT=T2-T1 =98.9 °C-23.9°C=75°C

specific heat constant for water is 4.18 j/g°C

therefore ΔH=2.9 g*4.18 j/g°C*75°C

ΔH=909.15 j

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2 years ago

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