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2 years ago

What happens to a sheet of copper as the average kinetic energy of the copper molecules decreases?

Chemistry

2 answers:

JulsSmile [24]2 years ago

8 0

Answer:

<h2>It gets cooler.</h2>

Explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>

gregori [183]2 years ago

3 0

It gets cooler so the person above me is correct

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Draw the alkene formed when 1-heptyne is treated with hbr in the presence of peroxide.

Nimfa-mama [501]

<h2>Heptene formed is -</h2><h2> $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$ </h2>

Explanation:

The two possibilities when the peroxide is not present

$CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-C$ ≡ $CH +HBr$ → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_{2}$

$CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_2$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr_2-CH_3$

In presence peroxide,

$CH_3-CH_2-CH_2-CH_2-CH_2-C$ ≡ $CH$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.

This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
One mole of HBr adds to one mole of 1-heptane.
The structure of heptene formed is -

$CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

5 0

3 years ago

A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if

serg [7]

<h3>Answer:</h3>

78.75 K

<h3>Explanation:</h3>

<u>We are given;</u>

Initial pressure, P₁ = 500 torr
Initial temperature,T₁ = 225 K
Initial volume, V₁ = 3.3 L
Final volume, V₂ = 2.75 L
Final pressure, P₂ = 210 torr

We are required to calculate the new temperature, T₂

To find the new temperature, T₂ we are going to use the combined gas law;
According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

= (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

= 78.75 K

Therefore, the new volume of the sample is 78.75 K

5 0

3 years ago

William measures a test tube and finds that the mass of the test tube is 5g. He places the lone reactant in the test tube and fi

iogann1982 [59]

86 percent is the percent yield for this experiment if he expected to produce 5g of product.

Explanation:

Given that:

mass of test tube = 5 grams

mass of test tube + reactant is 12.5 grams

mass of reactant = ( mass of test tube + reactant ) - (mass of test tube)

mass of reactant = 12.5 -5

= 7.5 grams

when 7.5 grams of reactant is heated mass of test tube was found to be 9.3 grams.

so mass of product formed = 9.3 - 5

= 4. 3 grams of product is formed (actual yield)

However, he expected the product to be 5 grams (theoretical yield)

Percent yield = $\frac{actual yield}{theoretical yield}$ x 100

putting the values in the formula:

percent yield = $\frac{4.3}{5}$ x 100

= 86 %

86 percent is the percent yield.

5 0

3 years ago

14. The flight will arrive<br>A. By<br>B. on<br>D. at<br>C. with

Marat540 [252]

Answer : A.By

Step by Step Explanation

7 0

2 years ago

Which one of the following is a combustion reaction?

Nady [450]

Well i have done a little of chemistry but i think it would be A. Of you look at whats reacting the product the ya A IS YOUR ANSWER I HOPE I DIDN'T GET IT WRONG

4 0

2 years ago