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Andrei [34K]
3 years ago
9

Need answers for Chemistry asap. Will give brainliest.

Chemistry
2 answers:
solniwko [45]3 years ago
7 0

Answer:

a) 0.4 moles

b) 0.3 moles

N76 [4]3 years ago
3 0

Answer:

Balance chemical equation is

O2(g) + 2H2(g) --> 2H20(g)

a. 0.20 mol 02 --> 0.225mol H20

b. 0.30 mol H2 --> 2.7mol H20

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Which of the following operations usually makes a substance dissolve faster in a solvent?
vovangra [49]

Answer:

B and C

Explanation:

powder dissolve faster than particles

the higher the temperature the faster the dissolving process

6 0
3 years ago
Can someone please help me
Alona [7]

Answer:

Potassium iodide increases the decomposition rate of hydrogen peroxide.

Explanation:

Potassium iodide increases the decomposition rate of hydrogen peroxide because potassium iodide act as a catalyst. A catalyst speed up the process of chemical reaction without reacting with the molecules present in reaction. If the potassium iodide is not present as a catalyst for the decomposition of hydrogen peroxide then the decomposition of hydrogen peroxide takes too much time because the catalyst is absent that speed up the reaction.

5 0
3 years ago
This answer please :))
r-ruslan [8.4K]

Answer: ya this one

Explanation: this is the one

4 0
3 years ago
The approximate recommended daily dietary intake of the amino acid valine, c5h11no2, is 2.60 g for a 100 kg adult. what is this
Murrr4er [49]
Answer is: <span>requirement of valine is 0,0222 mol for a100 kilograms adult.
</span>m(C₅H₁₁NO₂) = 2,60 g.
M(C₅H₁₁NO₂) = 5 · 12 + 11 · 1 + 1 · 14 + 2 · 16 · g/mol.
M(C₅H₁₁NO₂) = 117 g/mol.
n(C₅H₁₁NO₂) = m(C₅H₁₁NO₂) ÷ M(C₅H₁₁NO₂).
n(C₅H₁₁NO₂) = 2,60 g ÷ 117 g/mol.
n(C₅H₁₁NO₂) = 0,0222 mol.
n - amount of substance.
m - mass of substance.
M - molar mass of substance.
5 0
4 years ago
Read 2 more answers
A sample of solid iron is heated with an electrical coil. If 85.7 Joules of energy are added to a 14.3 gram sample initially at
Masja [62]

Answer:

The final temperature of the iron is:- 38.0 °C

Explanation:

The initial temperature = 24.7 °C

Let Final temperature = T °C

Using,

Q = m C ×ΔT

Where,  

Q is the heat absorbed by the iron = 85.7 J

C gas is the specific heat of the iron = 0.45 J/g  °C

m is the mass of iron = 14.3 g

ΔT is the change in temperature. ( T - 24.7 ) °C

Applying the values as:

<u>Q = m C ×ΔT  </u>

85.7 J = 14.3 g × 0.45 J/g  °C  × ( T - 24.7 ) °C

Solving for T, we get that:-

T = 38.0 °C

<u>The final temperature of the iron is:- 38.0 °C</u>

7 0
4 years ago
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