Question

A solid was found to be highly soluble in water. Treating separate portions of a solution of this solid with aqueous solutions of NaCl, NaBr, NaI, Na2SO4, Na2CO3, Na3PO4, NaOH, and Na2S produced no precipitates. Treatment of an aqueous solution of this solid with acid resulted in the formation of an odorless gas. This solid could be:a. PbSO3b. KBrc. Li2CO3d. (NH4)2Se. both PbSO3 and Li2CO3

Answer 1

Answer:

c. $Li_2CO_3$

Explanation:

Hello,

Due to the fact that an odorless gas was released, the chemical reaction between lithium carbonate and a random acid (for instance hydrochloric acid) turns out into:

$Li_2CO_3(s)+2HCl(aq)-->2LiCl(aq)+CO_2(g)+H_2O(l)$

It is known that carbonic acid is unstable and it quickly decomposes into water and carbon dioxide which is an odorless gas. In spite of the fact that the $PbSO_3$ releases $SO_2$ it isn't the solid since that gas is odorous.

Best regards.