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lesya692 [45]
3 years ago
15

A solid was found to be highly soluble in water. Treating separate portions of a solution of this solid with aqueous solutions o

f NaCl, NaBr, NaI, Na2SO4, Na2CO3, Na3PO4, NaOH, and Na2S produced no precipitates. Treatment of an aqueous solution of this solid with acid resulted in the formation of an odorless gas. This solid could be:a. PbSO3b. KBrc. Li2CO3d. (NH4)2Se. both PbSO3 and Li2CO3
Chemistry
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

c. Li_2CO_3

Explanation:

Hello,

Due to the fact that an odorless gas was released, the chemical reaction between lithium carbonate and a random acid (for instance hydrochloric acid) turns out into:

Li_2CO_3(s)+2HCl(aq)-->2LiCl(aq)+CO_2(g)+H_2O(l)

It is known that carbonic acid is unstable and it quickly decomposes into water and carbon dioxide which is an odorless gas. In spite of the fact that the PbSO_3 releases SO_2 it isn't the solid since that gas is odorous.

Best regards.

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alukav5142 [94]

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Explanation:

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Read 2 more answers
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