4. How many moles of Ca(HCO3)2 are present in 4.6 liters of a 3.5 molarity solution?
1 answer:
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= 2 × 23 + 2 × 52 + 2 × 16
= 182 grams
1 mole of weighs = 182 g
8 moles weigh = 8× 182
=
or
Answer:
1-ethyl-2-methyl cyclopropane.
Explanation:
- The structure of the molecule will be as shown in the attached image.
- The molecular formula of the compound is C₆H₁₂.
- It has 3 membered ring with 3 C atoms and two substituents one of them with one C atom (methyl) and the other with 2 C atoms (ethyl).
- The ring consist of 3 C atoms, so its name is cyclo propane.
- We numbering the atoms of the ring that give the ethyl substituent the low no. (1) and then methyl group take no. (2).
- <em>Thus, the name of the compound is 1-ethyl-2-methyl cyclopropane.</em>
