Question

. Write an equation for the combined gas law, using temperature in degrees Celsius. Explain why the Kelvin scale is convenient.

Answer 1

The combined gas law

$\displaystyle \frac{P.V}{t+273}=k$

Further explanation  

There are several gas equations in various processes:  

• 1. Avogadro's hypothesis  

In the same temperature and pressure, in the same volume conditions, the gas contains the same number of molecules  

So it applies: the ratio of gas volume will be equal to the ratio of gas moles

V1: V2 = n1: n2  

• 2. Boyle's Law  

At a fixed temperature, the gas volume is inversely proportional to the pressure applied  

p1.V1 = p2.V2  

• 3. Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

V1 / T1 = V2 / T2  

• 4. Gay Lussac's Law  

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature  

P1 / T1 = P2 / T2  

• 5. Law of Boyle-Gay-Lussac  

Combined with Boyle's law and Gay Lussac's law  

P1.V1 / T1 = P2.V2 / T2  

P1 = initial gas pressure (N / m2 or Pa)  

V1 = initial gas volume (m3)  

P2 = gas end pressure  

V2 = the final volume of gas  

T1 = initial gas temperature (K)  

T2 = gas end temperature  

Can be concluded

Boyle's law at constant T, P = 1 / V ⇒PV = k

Charles's law, at constant P, V = T ⇒V/T = k

Gay Lussac's Law , constant V, P=T⇒P/T = k

Avogadro's law, at constant P and T, V = n  

So an equation for the combined gas law :

$\large{\boxed{\bold{\frac{P.V}{T}=k}}$

$\large{\boxed{\bold{\frac{P.V}{t+273}=k}}$

Become the general ideal gas equation  

PV = nRT  

PV = NkT  

N = number of gas particles  

n = number of moles  

R = gas constant (8,31.10³ J / kmole K  

k = Boltzmann constant (1,38.10⁻²³)  

n = = N / No  

n = m / M  

n = mole  

No = Avogadro number (6.02.10²³)  

m = mass  

M = relative molecular mass  

Absolute zero point of the Kelvin scale can better indicate the condition of a substance that has frozen, so the Kelvin scale is always positive and easy to calculate

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Keywords : ideal gas law,the combined gas law,Kelvin scale

Answer 2

Answer:

$PV= nR(T+273.16)$ for an ideal gas

$(P+ \frac{an^{2}}{V^{2} } )\times(V-nb)=nR(T+273.16)$ for real gases

Explanation:

Combined gas law is a law that combines, Charles', Boyle's and Gay-Lussac law for gas molecules.

Temperature on Celsius scale can be converted to temperature in Kelvin scale by adding 273.16. As 0 degree Celsius is equivalent to 273.16 K.

Now, the combined gas law is:

$PV= nR(T+273.16)$ for ideal gas

$(P+ \frac{an^{2}}{V^{2} } )\times(V-nb)=nR(T+273.16)$ for real gas

P= pressure of the gas (in Pa)

V= volume the gas occupies(in m³)

n= number of moles

R= Universal gas constant

T= temperature in degree Celsius.

a and b are van der Waals constants

Kelvin scale is convenient because gases can be cooled to very low temperatures. Such temperature readings on Celsius scale turn out to be negative numbers. Hence, it is easy to work with positive numbers. Also, 0K is a temperature that is yet to be achieved physically.