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Zanzabum
3 years ago
13

Can the sides of a triangle have lengths 2, 5, and 9? Help?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0
No, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. ( ex; 3,4,8. 3+4=7 ( the two side lengths) and the third side length is 8, which is a bigger number than 7, which means it’s not possible because the third side length is a larger number than the two side lengths. Hope that helped you :)
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For 1-3 write an equivalent expression <br> 1.) -3(7+5g) <br> 2.) (x+7)+3y <br> 3.) 2/9-1/5*x
alukav5142 [94]

\huge \bf༆ Answer ༄

The equivalent expressions are ~

<h3>Question : 1 </h3>

  • \sf \:  - 3(7 + 5g)

  • \sf - 21 - 15g

  • \sf- 15g - 21
<h3>Question : 2</h3>

  • \sf \:( x + 7) + 3y

  • \sf \: x + 7 + 3y

  • \sf \: x + 3y + 7
<h3>Question : 3 </h3>

  • \sf \dfrac{2}{9}  -  \dfrac{1}{5x}

  • \sf \dfrac{10x  - 9}{45x}

7 0
2 years ago
Read 2 more answers
An object is propelled vertically upward from the top of a​ 256-foot building. The quadratic function​ s(t) = ​-16t squared ​+ 1
Aneli [31]

Answer: t= 13.2 seconds

Step-by-step explanation:

The quadratic function for ball's height in terms of time t is given as

s(t)= -16t² +192t + 256

Now we want to find out the time at which the ball hits the ground.

When the ball hits the ground, the height of the ball will become zero so in the above equation we can put s(t)=0

0= -16t² +192t + 256

or 16t² -192t - 256 = 0

Solving this quadratic equation, we have

t= 13.211 and t= -1.211

Since time can't be negative so

t= 13.2 seconds

6 0
3 years ago
name the translation image of abc after a reflection across line t and then a reflection across line r.
Rina8888 [55]

Is there an image that goes along with this question? I think that I could help you if there was an image.

8 0
4 years ago
Find the area of the irregular figure. Round your answer to the nearest hundredth if necessary.
Rudiy27

Answer:

Step-by-step explanation:

Area of the figure = Area of semicircle + area of rectangle

Area of semicircle:

d = 14 mm

r = 14/2 = 7 mm

Area = (1/2)πr²

=\frac{1}{2}*\frac{22}{7}*7*7\\

=11 *7

= 77 mm²

Area of rectangle:

length = 14 mm

Width = 10 mm

Area = length *width

       = 14 * 10

       = 140 mm²

Area of the figure = 77 + 140 = 217 mm²

3 0
3 years ago
Pls solve for x! will give brainly!
Tju [1.3M]

Answer:

12

Step-by-step explanation:

5 0
3 years ago
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