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topjm [15]
3 years ago
7

Factor the expression. ( q2 − r2s) ( q4 + q2r2s + r4s2)

Mathematics
2 answers:
Natalija [7]3 years ago
4 0

Answer:

(q^2-r^2s)(q^4+q^2r^2s+r^4s^2)=q^6-r^6s^3

Step-by-step explanation:

Given : Expression (q^2-r^2s)(q^4+q^2r^2s+r^4s^2)

To find : Factor the expression?

Solution :

The given expression (q^2-r^2s)(q^4+q^2r^2s+r^4s^2) is the factored form of q^6-r^6s^3  

Now, We solve to get the form

a^3-b^3=(a-b)(a^2+ab+b^2)

Taking RHS and compare with the given expression        

(q^2-r^2s)(q^4+q^2r^2s+r^4s^2)    

Where, a=q^2,b=r^2s

=(q^2)^3-(r^2s)^3

=q^6-r^6s^3

Therefore, (q^2-r^2s)(q^4+q^2r^2s+r^4s^2)=q^6-r^6s^3

melomori [17]3 years ago
3 0

(5q2 − r2s)(25q^4+5q^2r^2s+1r^4s^2)

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