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Maru [420]
3 years ago
9

How many mm are equal to 0.003 dm?

Mathematics
2 answers:
lions [1.4K]3 years ago
5 0

Answer:

0.3mm

Step-by-step explanation:

Multiply the length value by 100.

egoroff_w [7]3 years ago
4 0

Answer:

.3

Step-by-step explanation:

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Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me
amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

H_{0}: p \geq 0.6

And the alternate hypothesis is:

H_{a}: p < 0.6

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

\mu = 0.6

\sigma = \sqrt{0.6*0.4}

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that n = 575, X = \frac{338}{575} = 0.5878

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}

z = -0.6

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

Since 0.2743 > 0.1, the threshold probably was met.

3 0
3 years ago
In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
It takes Karl 6 hours to drive 372 miles. If he drives at a constant speed during the 6 hours, what is his unit rate? At this ra
Vikki [24]
He drives 62 miles per hour.
And yes, you are right, (496 miles after 8 hours)
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csf%20%5Clarge%20%5C%3A%20If%20%20%5C%3A%20y%20%3D%20Sin%20x%20%20%5C%3A%20%2A%20Cos%20%2
DIA [1.3K]

Answer:

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Solution:

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8 0
2 years ago
Read 2 more answers
Five adult tickets and three child tickets for a movie costs £55. The cost of buying two adult tickets and three child tickets i
Allisa [31]

Answer:

  • adult £8
  • child £5

Step-by-step explanation:

If you look at the numbers you are given, you see that the first purchase has 3 more adult tickets than the second purchase, and its cost is £24 more. This means an adult ticket costs £24/3 = £8.

Two adult tickets will cost 2×£8 = £16, so three child tickets cost ...

  £31 -16 = £15

Each child ticket is then £15/3 = £5.

An adult ticket costs £8; a child ticket costs £5.

7 0
3 years ago
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