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Lady bird [3.3K]
3 years ago
8

A train travels at a constant speed of 24 miles per hour. Which equation and table show the correct relationship between h , the

number of hours, and d , the distance traveled?

Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

it would be C. d=24h

Step-by-step explanation:

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Correct answers only!
alina1380 [7]

Answer:

$39

Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 30 × 10/100 × 3

I = $9

She have = 30 + 9 = $39

3 0
3 years ago
What is 1/2 times 2 times 1.7
inn [45]

Answer:

1.7

Step-by-step explanation:

1/2 (2 x anything) = anything

1/2 cancels out the 2

7 0
3 years ago
Read 2 more answers
Simplify the radical expression. Show all your steps. <br><br> √363 - 3√27
siniylev [52]

Answer:

2 sqrt(3)

Step-by-step explanation:

Simplify the following:

sqrt(363) - 3 sqrt(27)

sqrt(27) = sqrt(3^3) = 3 sqrt(3):

sqrt(363) - 33 sqrt(3)

sqrt(363) = sqrt(3×11^2) = 11 sqrt(3):

11 sqrt(3) - 3×3 sqrt(3)

-3×3 = -9:

11 sqrt(3) + -9 sqrt(3)

11 sqrt(3) - 9 sqrt(3) = 2 sqrt(3):

Answer: 2 sqrt(3)

3 0
3 years ago
What is the percent of decrease from 10 to 3?<br>Write your answer using a percent sign (%).<br>​
Nadya [2.5K]

Answer:

Convert the decimal to a percentage by multiplying the decimal by  

100 .

Step-by-step explanation:

4 0
3 years ago
The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers
Elis [28]

Answer:

The numbers are 23 and 7  

Step-by-step explanation:

1. Set up the equations

   Let x = the greater number

  and y = the smaller number. Then

(1) x - y = 16

       4y = 4 times the smaller number and

  4y - 5 = 5 less than 4 times the smaller number. Then

(2)     x = 4y - 5

You have a system of two equations:

\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}

2. Solve the equations

\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}

The larger number is 23; the smaller number is 7.

3. Check

\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}

OK.

3 0
3 years ago
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