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valentinak56 [21]
3 years ago
12

Hold a pocket mirror about half an arm’s length from your face and see how much of your face you see in the mirror. To be able t

o see more of your face, should you hold the mirror closer or farther, or would you have to have a larger mirror?
Physics
1 answer:
enyata [817]3 years ago
3 0

Answer:

The size of the mirror must be half of the size of your face.

Explanation:

As we know that pocket mirror is a plane mirror, for the plane mirror, distance of a person from the mirror does not affect the image formed by mirror. But the height of the mirror must be half of the height of the person to see the whole face. It is because pocket mirror is between your head and the virtual image formed, to see the virtual image, your face rays must strike the reflecting surface, for that purpose the size of the mirror must be large enough so that your face rays can strike the reflecting surface easily.

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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.35 kg to a friend standing in front of him
nataly862011 [7]

Answer:

a) u_c=0\ m.s^{-1}       &        m_c.v_c=m_b.v_b\times \cos\theta

b) v_c=0.0566\ m.s^{-1}

c) p_e=2.9218\ kg.m.s^{-1}

Explanation:

Given:

mass of the book, m_b=1.35\ kg

combined mass of the student and the skateboard, m_c=97\ kg

initial velocity of the book, v_b=4.61\ m.s^{-1}

angle of projection of the book from the horizontal, \theta=28^{\circ}

a)

velocity of the student before throwing the book:

Since the student is initially at rest and no net force acts on the student so it remains in rest according to the Newton's first law of motion.

u_c=0\ m.s^{-1}

where:

u_c= initial velocity of the student

velocity of the student after throwing the book:

Since the student applies a force on the book while throwing it and the student standing on the skate will an elastic collision like situation on throwing the book.

m_c.v_c=m_b.v_b\times \cos\theta

where:

v_c= final velcotiy of the student after throwing the book

b)

m_c.v_c=m_b.v_b\times \cos\theta

97\times v_c=1.35\times 4.61\cos28

v_c=0.0566\ m.s^{-1}

c)

Since there is no movement of the student in the vertical direction, so the total momentum transfer to the earth will be equal to the momentum of the book in vertical direction.

p_e=m_b.v_b\sin\theta

p_e=1.35\times 4.61\times \sin28^{\circ}

p_e=2.9218\ kg.m.s^{-1}

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It must gain an electron because if the proton number was to change it would no longer be the same element.
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The answer would be D)Apathy
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Answer:

a

Explanation:

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Answer:

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