The force that keeps the puck moving is 0.25 N while the velocity of the puck is 3.7 m/s.
<h3>What is the centripetal force?</h3>
We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.
The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;
Centripetal force = Weight of object = mg
m = mass of the object
g = acceleration due to gravity
Then;
W = 0.026 Kg * 9.8 m/s^2
W = 0.25 N
To obtain the velocity of the object;
FT = mv^2/r
v = √ FT r/m
v = √0.25 * 1.4/0.026
v = 3.7 m/s
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It looks like when the object is in "freefall".
Substitute your values into the formula:
W = Work done = 288
= 360
Solve to find e:
e = 288 ÷ 360 = 0.8
Convert e to a percentage by multiplying by 100.
0.8 × 100 = 80
<h2>D. 80%</h2>
Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector, 
= 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ = × cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R
= × sin(θ)
∴ R = 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em><em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R·j
∴ ≈ -16.07·i + 19.15j)
The answer to the question asked above is that amorphous solid's atoms and molecules are not arranged in a definite lattice pattern, while crystalline are arranged definitely in a lattice pattern.
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