Answer:
The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Explanation:
Electric potential is given as;
V = E*r
where;
E is the electric field strength, = kq/r²
V = ( kq/r²)*r
V = kq/r
k is coulomb's constant = 8.99 X 10⁹ Nm²/C²
q is the charge of the particles = 1.6 X 10⁻¹⁹ C
r is the distance between the particles = 859 nm
At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm
V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)
V = 3.349 X 10⁻³ Volts
Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Answer:
400 trips
Explanation:
Mechanical energy needed to climb 14 m by a man of 68 kg
= mgh
= 68 x 9.8 x 14
= 9330 J
1 Kg of fat releases 3.77 x 10⁷ J of energy
.45 kg of fat releases 1.6965 x 10⁷ J of energy
22% is converted into mechanical energy
so 22% of 1.6965 x 10⁷ J
= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.
one trip of climbing of 14 m requires 9330 J of mechanical energy
no of such trip possible with given mechanical energy
= 3732.3 x 10³ / 9330
= 400 trips
Answer:
Gravity.The weak force.
Electromagnetism.The strong force.
The most common form of angina is stable angina.
C. stable
