3 years ago

Why it is easier to lift a small stone but harder to lift heavy one on the surface of Earth

1 answer:

8 0

Answer:

since small stone has less mass so the gravitational pull of the earth is lesser in case of this but this is not for the bigger stone as the gravitational pull of the earth is greater...

PLEASE MARK BRAINLIEST!!!!!

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A small marble attached to a massless thread is hung from a horizontal support. When the marble is pulled back a small distance

s2008m [1.1K]

Answer:

f' = 2 f

Explanation:

The frequency of the pendulum that swings in simple harmonic motion is given by :

$f={2\pi}\sqrt{\dfrac{l}{g}}$

Where

l is the length of pendulum

g is the acceleration due to gravity

If the length of the thread is increased by a factor of 4, such that, l' = 4 l, let f' is the new frequency such that,

$f'={2\pi}\sqrt{\dfrac{l' }{g}}$

$f'={2\pi}\sqrt{\dfrac{4l}{g}}$

$f'=2\times {2\pi}\sqrt{\dfrac{l}{g}}$

f' = 2 f

So, the new frequency of the pendulum will become 2 time of initial frequency. Hence, the correct option is (b) "2f"

3 0

3 years ago

Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his

just olya [345]

The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.

4 0

4 years ago

Read 2 more answers

A 70-kg astronaut is space walking outside the space capsuleand is stationary when the tether line breaks. As a means of returni

Bogdan [553]

Answer:

0.4 m/s

Explanation:

Law of conservation of momentum tell us that the change in momentum of the hammer will be equal to the change in momentum of the astronaut

change in momentum of hammer = change in momentum of astronaut

2 kg (14 m/s - 0 m/s) = 70 kg * (v-0)

v = 0.4 m/s