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egoroff_w [7]
3 years ago
15

Mt. Everest is 20,028 feet high. How many miles is this? ( there are 5,280 feet in a mile)

Physics
2 answers:
MAXImum [283]3 years ago
6 0

20,028 feet is 3.793 miles

The summit of Mt. Everest is 29,029 ft above sea level. That's 5.498 miles.

Nana76 [90]3 years ago
3 0

<u>Answer:</u>

Mt. Everest is 3.79 miles high.

<u>Solution: </u>

Everest is 20,028 ft high.

As given, 1 mile = 5280 ft

So 1 \mathrm{ft}=\left(\frac{1}{5280}\right) \mathrm{mile}

Then 20,028 ft will be =20028 \times\left(\frac{1}{5280}\right) \text { mile }=\left(\frac{20028}{5280}\right) \text { mile }

=\left(\frac{10014}{2640}\right) \text { mile }=\frac{5007}{1320} \text { mile }=3.79 \text { mile }

The height of Everest is 3.79 miles .

Note: The actual height of Mt. everest is 5.4979 miles or 29029 ft.

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A person walks due south from point A for 500 yards and then due west for 300 yards, arriving at point B. Answer the following q
Pepsi [2]

The total displacement of the person walking from point A to point B is 300 yards.

As shown in the figure we can conclude that the required method to calculate the total displacement is the Pythagoras theorem.

<h3>Pythagoras theorem in brief :</h3>

According to the Pythagorean Theorem, the square that represents the hypotenuse, or side of a right triangle that faces the right angle, is equal to the total of the squares on the triangle's legs.(or, in popular algebraic notation, a^2 + b^2 = c^2).

<h3>Calculation: </h3>

Let,

a = 500

b=  300

Hence by using Pythagoras' theorem

Total displacement of the person = \sqrt{500^{2}  + 300^{2} } = \sqrt{900000} = 300

Thus the total displacement of the person from starting point is 300 yards.

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brainly.com/question/11188852

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2 years ago
Equations E = 1 2πε0 qd z3 and E = 1 2πε0 P z3 are approximations of the magnitude of the electric field of an electric dipole,
tamaranim1 [39]

Answer:

The ratio of E_{app} and E_{act} is 0.9754

Explanation:

Given that,

Distance z = 4.50 d

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We need to calculate the ratio of E_{act} and E_{app}

Using formula

\dfrac{E_{app}}{E_{act}}=\dfrac{\dfrac{P}{2\pi\epsilon_{0}\times z^3}}{\dfrac{Pz}{2\pi\epsilon_{0}\times (z^2-\dfrac{d^2}{4})^2}}

\dfrac{E_{app}}{E_{act}}=\dfrac{(z^2-\dfrac{d^2}{4})^2}{z^3(z)}

Put the value into the formula

\dfrac{E_{app}}{E_{act}}=\dfrac{((4.50d)^2-\dfrac{d^2}{4})^2}{(4.50d)^3\times4.50d}

\dfrac{E_{app}}{E_{act}}=0.9754

Hence, The ratio of E_{app} and E_{act} is 0.9754

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