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egoroff_w [7]
3 years ago
15

Mt. Everest is 20,028 feet high. How many miles is this? ( there are 5,280 feet in a mile)

Physics
2 answers:
MAXImum [283]3 years ago
6 0

20,028 feet is 3.793 miles

The summit of Mt. Everest is 29,029 ft above sea level. That's 5.498 miles.

Nana76 [90]3 years ago
3 0

<u>Answer:</u>

Mt. Everest is 3.79 miles high.

<u>Solution: </u>

Everest is 20,028 ft high.

As given, 1 mile = 5280 ft

So 1 \mathrm{ft}=\left(\frac{1}{5280}\right) \mathrm{mile}

Then 20,028 ft will be =20028 \times\left(\frac{1}{5280}\right) \text { mile }=\left(\frac{20028}{5280}\right) \text { mile }

=\left(\frac{10014}{2640}\right) \text { mile }=\frac{5007}{1320} \text { mile }=3.79 \text { mile }

The height of Everest is 3.79 miles .

Note: The actual height of Mt. everest is 5.4979 miles or 29029 ft.

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You are coasting on your 12-kg bicycle at 13 m/s and a 5.0-g bug splatters on your helmet. The bug was initially moving at 1.5 m
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Answer:

a) Pi,c = 1066 kgm/s

b) Pi,b = 0.0075 kgm/s  

c) ΔV = - 0.0007 m/s

d) ΔV = - 0.0008 m/s

Explanation:

Given:-

- The mass of the bicycle, mc = 12 kg

- The mass of passenger, mp = 70 kg

- The mass of the bug, mb = 5.0 g

- The initial speed of the bicycle, vpi = 13 m/s

- The initial speed of the bug, vbi = 1.5 m/s

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a.What is the initial momentum of you plus your bicycle?

b.What is the initial momentum of the bug?

c.What is your change in velocity due to the collision the bug?

d.What would the change in velocity have been if the bug were traveling in the opposite direction?

Solution:-

- First we will set our one dimensional coordinate system, taking right to be positive in the direction of bicycle.

- The initial linear momentum (Pi,c) of the passenger and the bicycle would be:

                       Pi,c = vpi* ( mc + mp)

                       Pi,c = 13* ( 12+ 70 )

                       Pi,c = 1066 kgm/s  

- The initial linear momentum (Pi,b) of the bug would be:

                       Pi,b = vbi*mb

                       Pi,b = 0.005*1.5

                       Pi,b = 0.0075 kgm/s  

- We will consider the bicycle, the passenger and the bug as a system in isolation on which no external unbalanced forces are acting. This validates the use of linear conservation of momentum.

- The bicycle, passenger and bug all travel in the (+x) direction after the bug splatters on the helmet.

                       Pi = Pf

                       Pi,c + Pi,b = V*(mb + mc + mp)

Where,    V : The velocity of the (bicycle, passenger and bug) after collision.

                      1066 + 0.0075 = V*( 0.005 + 12 + 70 )

                      V = 1066.0075 / 82.005

                      V = 12.9993 m/s

- The change in velocity is Δv = 13 - 12.9993 =  - 0.00070 m/s      

- If the bug travels in the opposite direction then the sign of the initial momentum of the bug changes from (+) to (-).

- We will apply the linear conservation of momentum similarly.

                      Pi = Pf

                      Pi,c + Pi,b = V*(mb + mc + mp)        

                      1066 - 0.0075 = V*( 0.005 + 12 + 70 )

                      V = 1065.9925 / 82.005

                      V = 12.99911 m/s

- The change in velocity is Δv = 13 - 12.99911 =  -0.00088 m/s      

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