(a) The value of the gravitational acceleration is given by:
where
is the gravitational constant
M is the Earth's mass
is the Earth's radius at the pole
If we use the value for g given by the problem, 
, and we rearrange the equation above, we find the value of the Earth's mass:
(b) The value we found for the Earth's mass is 
, and we see that this value is slightly larger than the accepted value of 
.
Answer:
a) v = 13.8 m / s
, b) a = 95.49 m / s²
, c) a force that goes to the center of the carnival ride and d) μ = 0.10
Explanation:
For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics
a) reduce the magnitudes to the SI system
w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s
The equation that relates linear and angular velocity is
v = w r
v = 6.91 2
v = 13.8 m / s
b) centripetal acceleration is given by
a = v² / r = w² r
a = 6.91² 2
a = 95.49 m / s²
c) this acceleration is produced by a force that goes to the center of the carnival ride
d) Here we use Newton's second law
fr -W = 0
fr = W
μ N = mg
Radial shaft
N = m a
N = m w² r
μ m w² r = m g
μ = g / w² r
μ = 9.8 / 6.91² 2
μ = 0.10
