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Deffense [45]
3 years ago
9

On one day a rickshaw puller earned 80.out of his earning he spent 68÷5 on tea and snacks,51÷2 on food and 22÷5 on repair of the

rickshaw.How much did he save on that?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0
Answer: $56.50
==================================
(instead of dividing each of them individually and them subtracting them one by one, combine them together as a fraction first and then subtract)

80 - (68/5 + 51/2 + 22/5)
= 80 - (136/10 + 255/10 + 44/10)
= 80 - (435/10)
= 80 - 43.5
= 56.5

He saved $56.50 on that
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So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;

2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5

Hope this helps you. Any questions please ask.
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Answer:

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Step-by-step explanation:

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