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Basile [38]
3 years ago
12

Name the property of a quality that justifies the following statement:

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0

Answer: B Addition property of equality

Step-by-step explanation: the property: a=b, so a+c = b+c

Grace [21]3 years ago
4 0

Answer:

b.

Step-by-step explanation:

its basically saying since x equals 10 and 10 is on both sides that if you add y to both sides itll still be equal hence, addition property of equality.

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3 years ago
What is the circumference of a circle with a diameter of 5 feet? use 3.14 for pi
artcher [175]

Answer:

15.7

Step-by-step explanation:

Circumference= πd

d= Diameter

7 0
3 years ago
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avanturin [10]

Answer:

d=4.5t

Step-by-step explanation:

in two hours, Francine went 9 miles

9/2=4.5

the distance equals 4.5 times each cycling time.

d=4.5t

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2 years ago
Read 2 more answers
The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
Aleks04 [339]

Answer:

<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

6 = 2+(n-1)4/7

6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

32 = 4n

n = 32/4

n = 8

8 0
3 years ago
Las llantas de un automóvil pequeño tiene una medida de 14 pulgadas de diámetro.Realiza la gráfica de una de las llantas colocan
LiRa [457]

Answer:

Invitamos cordial a revisar la imagen adjunta abajo para mayor detalle sobre la gráfica de las llantas.

La forma general de la circunferencia de la llanta está representada por x^{2}+y^{2}-49 = 0.

Step-by-step explanation:

A continuación, anexamos una representación de las llantas del automóvil como una circunferencia centrada en el origen y con un diámetro de 14 pulgadas, es decir, un radio de 7 pulgadas.

La ecuación estándar de la circunferencia centrada en un punto dado y con un radio determinado está definida por:

(x-h)^{2}+(y-k)^{2} =r^{2} (1)

Donde:

h, k - Coordenadas del centro de la circunferencia, medidas en pulgadas.

r - Radio de la circunferencia, medido en pulgadas.

Si conocemos que h = 0\,in, k = 0\,in y r = 7\,in, entonces la ecuación estándar que representa a la circunferencia de la llanta es:

x^{2}+y^{2} = 49

Ahora, la ecuación general de la circunferencia centrada en el origen satisface la siguiente expresión:

A\cdot x^{2}+A\cdot y^{2}+B = 0 (2)

Donde A, B son los coeficientes de forma de la circunferencia.

Entonces, la forma general de la circunferencia de la llanta está representada por la siguiente expresión:

x^{2}+y^{2}-49 = 0

6 0
3 years ago
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