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andrew-mc [135]
3 years ago
13

Find the sum of the geometric series.

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

Sum=\frac{32}{5}=6.4

Step-by-step explanation:

we are given geometric  series as

8-2+\frac{1}{2}-\frac{1}{8}+.......

we can use infinite sum formula

sum=\frac{a}{1-r}

where

a is first term

r is common ratio

so, we have

a=8

r=\frac{-2}{8}

r=-\frac{1}{4}

now, we can plug values

sum=\frac{8}{1-(-\frac{1}{4})}

Sum=\frac{32}{5}=6.4

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What is the value of x in the diagram?
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Answer:

x=5

Step-by-step explanation:

Since this is a right triangle, we can use the pythagorean theorem

a^2 + b^2 = c^2

x^2+ ( 2x+2)^2 = (2x+3)^2

FOIL the squared terms

x^2 +(4x^2 + 4x+4x+4) = 4x^2 + 6x+6x +9

Combine like terms

5x^2+8x +4 = 4x^2 +12x +9

Subtract  4x^2 +12x +9 from each side

5x^2+8x +4  -4x^2 -12x -9= 4x^2 +12x +9-4x^2 -12x -9

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Using the zero product property

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3 years ago
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Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

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RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

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LHS = y = 6

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(i) When x = -2

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OPTION B is eliminated.

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(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

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